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Norma-Jean [14]
3 years ago
13

A carbon-carbon double bond has a greater bond energy than a carbon-carbon single bond. Because of the greater bond energy, a ca

rbon-carbon double bond is (stronger,weaker) and (longer,shorter) than a carbon-carbon single bond.
Chemistry
2 answers:
Mrac [35]3 years ago
8 0

The first blank is stronger

and the second blank is shorter

:)

Ronch [10]3 years ago
5 0

<u>Answer:</u> Carbon-carbon double bond is stronger and shorter than the single bond.

<u>Explanation:</u>

It is given that carbon-carbon double bond has greater energy than the carbon-carbon single bond.

Bond energy is directly proportional to the bond strength, which means that the double bond will have greater strength than single bond and triple bond has the greatest strength of all the bonds.

\text{Bond energy}\propto \text{Bond strength}

Bond energy is inversely proportional to the bond length of the carbon-carbon bond. This means that more is the bond energy, shorter will be the bond and vice-versa.

\text{Bond energy}\propto \frac{1}{\text{Bond Length}}

Hence, carbon-carbon double bond is stronger and shorter than the single bond.

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What is Y? 222/86 Rn A/z + 4/2He
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^{222}_{\phantom{2}86}\text{Rn} \to ^{218}_{\phantom{2}84}\text{Po}+ ^{4}_{2}\text{He}

Y is Po-218.

  • A = 218
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<h3>Explanation </h3>

^{222}_{\phantom{2}86}\text{Rn} \to ^{A}_{Z}\text{Y}+ ^{4}_{2}\text{He}

Here's the symbol of a particle in a nuclear reaction. ^{A}_{Z}\text{Y}.

A stands for mass number. Z stands for atomic number. Both numbers shall conserve in a nuclear reaction.

  • The mass number on the left hand side is 222.
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  • 222 = A + 4.
  • A = 218

So is the case for the atomic number. Try figure out the atomic number of Y using the same approach.

  • The atomic number on the left hand side is 86.
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What element is Y? The atomic number of Y is 84. Refer to a periodic table. Element 84 corresponds to Po (polonium). Y is Polonium-218. The symbol of Y should be written as ^{218}_{\phantom{2}84}\text{Po}. Hence the equation:

^{222}_{\phantom{2}86}\text{Rn} \to ^{218}_{\phantom{2}84}\text{Po}+ ^{4}_{2}\text{He}.

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