Answer:
2= its color
Explanation:
Transition elements are present in the middle of periodic table. These are d-block elements.
These are 38 elements.
All transition elements have partially filled d orbitals.
They showed color in compound because of d-d transition.
During the d-d transition electron absorbed the energy and emit the reminder energy. The emission is usually in the form of color light.
The color of ion is complementary to the absorbed color.
The transition elements are used as a catalyst in industries such as polymer, petroleum industries.
They are ductile, conduct heat and electricity.
Liquid, in a liquid state of matter, particles will flow over eachother, the forces between the particles are strong enough to hold a certain volume but not strong enough to keep the molecules sliding over each other.
1,g 2b 3c 4a 6e 7f !!!!!!!!!!!!
Explanation:
When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.
As it is given that there are 
moles of iodine heptafluoride are present. Molar mass of 
is 259.9 g/mol. Molar mass of 
is 227.94 g/mol and molar mass of HF is 20.01 g/mol.
Now, according to the reaction equation M gives M 
.
Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).
Hence, calculate the concentration of into the solution as follows.
Concentration = 
= 
= 
mol/L
or, = 0.047 M
Now, as 1 mol of produces 7 mol HF. So, 
M HF.
Therefore, concentration of HF will be calculated as follows.
Concentration of HF = 
= 0.33 M
Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.
The reaction for the combustion of methane can be expressed as follows.
CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
moles of CO2 = (5.6 L) / (22.4 L/1 mole)
moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
= 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane.
