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storchak [24]
3 years ago
15

Solve for the varible y: 2y+4=6

Mathematics
2 answers:
sattari [20]3 years ago
7 0
2y+4=6

First, subtract the 4 from both sides:
2y+4-4=6-4
Simplify:
2y=2
Divide both sides by 2:
y=1
puteri [66]3 years ago
4 0
The correct answer is y = 1. Hope this helps. (:
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Please do the area and perimeter for both questions! And if u can please explain how! Thank you
KiRa [710]
Question 1 - You need to split the L shape into  2 shapes.

6mm x 2mm = 12mm

and

5mm x 2mm = 10mm

add 12mm and 10mm 
the area is 22mm squared (a little 2 above the mm)

question 2 - you need to do the same

4mm x 2mm = 8mm squared 
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area - 22mm squared






6 0
3 years ago
Read 2 more answers
Convert the equation from rectangular to polar from x^2+Y^2=5y
Inessa05 [86]

Answer:

dy/dx=-2y-5/2x

Step-by-step explanation:

7 0
2 years ago
What is the greatest number of tables that can be made? Explain how did you decide on this number?
emmasim [6.3K]

The greatest number of tables that can be made is; 24 tables

<h3>Limiting Resources</h3>

To determine the limiting factor;

  • We must divide the number of all factors available by 72.

Hence, it goes that;

  • Only, 48/72= 0.66 balloons per chair
  • Only 24/72 = 0.33 flowers per chair
  • Only 32/72 = 0.44 candles per chair

However, it follows from the question that; the same number of centerpieces be used on each table.

Hence, the ratio of flowers per chair is lowest and hence, 72×0.33 flowers are used, 24 tables can therefore be set up.

Read more on limiting resources;

brainly.com/question/19231521

6 0
2 years ago
The product of , and the sum of a number and - 4 is less than or equal to 64.
lozanna [386]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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