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Artyom0805 [142]

3 years ago

8

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

l velicity of +5800m/s, while Rocket B has an initial velocity of +8600m/s. After a time t both rockets are again side by side, the displacement of each being zero. The acceleration of rocket A is -15m/s^2. What is the acceleration of rocket B?

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

-22.2 m/s²

Explanation:

The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:

(1) $x=\frac{1}{2}at^2+v_0t+x_0$

For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:

(2) $0=\frac{1}{2}at^2+v_0t$

Solving for time t:

$-\frac{1}{2}at^2=v_0t$

(3) $t=-\frac{2v_0}{a}$

The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:

(4) $\frac{v_{0A}}{a_A}=\frac{v_{0B}}{a_B}$

Solving equation 4 for acceleration of rocket B:

(5) $a_B=a_A\frac{v_{0B}}{v_{0A}}$

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Brayden and Riku now use their skills to work a problem. Find the equivalent resistance, the current supplied by the battery and

Liono4ka [1.6K]

a) $5 \Omega$ , 1.6 A

b) $6 \Omega$ , 1.33 A

Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

$R=R_1+R_2$

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$R_1=4\Omega$

$R_2=1 \Omega$

Therefore, the equivalent resistance is

$R=4+1=5 \Omega$

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$I=\frac{V}{R}$

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$I=\frac{8}{5}=1.6 A$

The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.

b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

$R=R_1+R_2+R_3$

where:

$R_1=4\Omega\\R_2=1\Omega\\R_3=1\Omega$

Substituting, we find the equivalent resistance:

$R=4+1+1=6 \Omega$

Now we can find the current through the circuit by using again Ohm's Law:

$I=\frac{V}{R}$

where

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$R=6\Omega$ is the equivalent resistance

Substituting,

$I=\frac{8}{6}=1.33 A$

And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.

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3 years ago

group of students is making model cars that will be propelled by model rocket engines. These engines provide a nearly constant t

iris [78.8K]

Answer:

increase.

Explanation:

According to the newton’s second law of motion force is expressed as product of mass and acceleration.

F = m a

If the force acting is constant, then.

m∝ $\frac{1}{a}$

That is if the mass of object increases the acceleration decreases and vice versa. The above equation is used when the force acting on the body is constant.

As the thrust force from the rocket engine is constant throughout there will be a variation in the mass or acceleration.

Thus, it won't stay the same.

As the weight of the car is maximum at the start because of the fuel present in the rocket engine and minimum at the end as the fuel burns throughout the journey of the car. Weight will be minimum at the end and hence acceleration is maximum at the end.

Thus, it won't decrease.

As the acceleration is going from minimum at the start to maximum at the end, therefore it is continuously increases throughout its journey.

Thus, it will increase.

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