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mihalych1998 [28]
3 years ago
13

Inside a television picture tube there is a build-up of electrons (charge of 1.602 × 10^–19 C) with an average spacing of 38.0 n

anometers between electrons. Find the electric field inside the picture tube. (Round to three significant figures.)
Physics
2 answers:
Brut [27]3 years ago
8 0
The magnitude of electric field is produced by the electrons at a certain distance.

E = kQ/r²

where: 
E = electric field produced
Q = charge
r = distance
k = Coulomb Law constant 9 x10^9<span> N. m</span>2<span> / C</span><span>2

Given are the following:
Q = </span><span>1.602 × 10^–19 C
</span><span>r = 38 x 10^-9 m

Substitue the given:
E = </span>\frac{( 1.602 x 10^{-19} )( 9.0x10_{9} )}{(38x10^{-9}) ^{2} }

E = 998.476 kN/C


Helen [10]3 years ago
6 0
The answer is <span> 997,000 N/C</span>
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