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iren2701 [21]
3 years ago
5

Wade wants to buy sweaters. he has $175 and each sweater coast $12.00. write and solve an inequality to find how many sweaters h

e can buy and still have at least $55.
Mathematics
1 answer:
Wittaler [7]3 years ago
5 0
X = number of sweaters
175 - 55 > 12X
120 > 12X
10 > X
the most amount of sweaters he can buy is 10
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But I'm not too sure about it.
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3 years ago
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Foram prescritos 500mg de dipirona para uma criança com febre.Na unidade tem disponivel ampola de 1g/2ml.Quantos g vão ser admin
Valentin [98]

De acordo com a disponibilidade da unidade, há apenas a seguinte dosagem: 1g/2mL - ou seja, uma grama de dipirona a cada 2mL

O enunciado está meio mal formulado, pois é dito que foram prescritos 500mg de dipirona e é essa quantidade de farmaco que a criança tem que tomar. Deseja-se saber quantos mL deverao ser administrados.

Fazendo a classica regra de 3, podemos chegar no volume desejado:

(atentar que 500mg = 0,5g)

     g               mL

     1    ---------   2

    0,5  ---------  X    

1 . X = 0,5 . 2

<h3>X = 1mL</h3>

8 0
3 years ago
a television on sale for 1/4 off original price. Original price is 120 more then sale price. What is original price of tv
agasfer [191]

Answer:

Original Price = 160

Sale Price =40

Step-by-step explanation:

Let Original Price be x and Sale Price be y

y=1/4 of x   (Equation 1)

x=120+y     (Equation 2)

Put value of x from equation 2 in equation 1

y= (1/4)*(120+y)

y=120/4 + y/4

y-y/4=30

3y/4=30

y=30*4/3

y=40

Put value of y in Equation 2

x=120+40

x=160

4 0
3 years ago
A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p
____ [38]

Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

<u>step 1:-</u>

Given sample  size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

 Population proportion of employed individuals who work at home at least once per week  P = \frac{x}{n} =\frac{41}{200} =0.205

Q=1-P= 1-0.205 = 0.705

<u>step 2:-</u>

Now  \sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }

=0.0015

<u>step 3:-</u>

<u>Confidence intervals</u>

<u>using formula</u>

(P  -  Z_∝} \sqrt{\frac{P Q}{n},} (P  +  Z_∝} \sqrt{\frac{P Q}{n},

(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887

=0.20113,0.20887[/tex]

<u>conclusion:</u>-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

4 0
3 years ago
Mrs. Olive used 1 2/5 quarts of syrup and 5 3/10 quarts of water to make lemonade. How many quarts of lemonade did she make? * A
Flura [38]

Answer:

B. 6 7/10

Step-by-step explanation:

We solve the above y by carrying out addition.

The quarts of Lemonade she made is calculated as:

1 2/5 quarts of syrup + 5 3/10 quarts of water

= 1 + 5 + (2/5 + 3/10)

Lowest common denominator = 10

= 6 ( 4 + 3/10)

= 6 7/10 quarts of Lemonade

Mrs Olive made 6 7/10 quarts of Lemonade

3 0
3 years ago
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