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posledela
3 years ago
13

A 1500 kg car traveling at 90 km/hr East collides with a 3000 kg truck traveling at 60 km/hr South. They stick together and move

which direction?
Physics
1 answer:
EleoNora [17]3 years ago
8 0

Answer:

They both move towards South direction.

Explanation:

NB: The car traveling due east must be backing west and the car traveling due south must be backing north.

From their momentum in calculation below:

Momentum of the car traveling east is MU= 1500x90x1000/3600= 37,500kgm/s.

Momentum of car traveling due South =MU = 3000x60x1000/3600= 50,000. So, from here we see the the momentum of the car moving south has the high momemtum so they stick together and move towards the direction of south.

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Explanation:

SUPONIENDO QUE LA ACELERACIÓN DE LA GRAVEDAD ES 9.80 m/s^{2}

USANDO LA SEGUNDA LEY DE NEWTON:

<em>m</em> = 80.0 N/9.80 m/s^{2} = 8.16 kg

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3 years ago
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A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c
Delvig [45]

Answer:

E=\dfrac{\lambda }{2\pi \varepsilon _or}

Explanation:

Given that

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For hollow metal cylinder

Charge density=2 λ

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E_w=\dfrac{\lambda_{wire} }{2\pi \varepsilon _or}

E_w=\dfrac{\lambda }{2\pi \varepsilon _or}

Now the electric filed due to hollow metal cylinder

E_c=\dfrac{\lambda_{cylinder} }{2\pi \varepsilon _or}

E_c=\dfrac{2\lambda }{2\pi \varepsilon _or}

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At r<R

E=\dfrac{\lambda }{2\pi \varepsilon _or}

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3 years ago
Darlene jumps into a swimming pool. She is creating _____. deep water waves impact waves surface currents tidal waves
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A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
baherus [9]

Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

\Sigma \tau = 0

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- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
\tau = r \times F

Doing the summation using their respective lever arms:

0 = L Tsin\theta  - dF_g

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Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

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Answer:

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