Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up

Physics

1 answer:

Amiraneli [1.4K]4 years ago

6 0

Answer: 5 m/s^2

Explanation: You have to use a kinematics equation that Includes what you are given. So in this case you have Initial velocity, final velocity, and time. You’re looking for acceleration so you have everything you need to use an equation, the one without distance.

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Elena L [17]

Answer:

Explanation:

This problem can be solved with the conservation of the momentum.

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Hence, the result depends of the acceleration of the car. If the change in the speed is higher than the speed of the ball, it is probably that the ball will be behind the car or it will come back to the car.

If the ball is fired forward, and if the change in the speed of the car is not enogh, the ball will be in front of the car.

HOPE THIS HELPS!!

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3 years ago

A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh

Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC and the charge on bead B be 28nC - qnC

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4.8\times10^{-4} = $\frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}$