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nadezda [96]
3 years ago
9

You are asked to construct a mobile with four equal m = 141 kg masses, and three light rods of negligible mass and equal lengths

. The rods are of length 55 cm. (a) At what location on the level 1 rod should the free end of rod 2 be attached?
Physics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

The free end must be attached at a distance of 27.5 cm

Solution:

Mass, m = 141 kg

Length of the rods, L= 55 cm

Now,

As clear from fig. 1:

The free end of the rod 2 must be attached at:

F = 2 W

WL = W(55 - L)

2L = 55

L = 27.5 cm

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Katyanochek1 [597]

Answer:

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                      \tau = FR_B  - F_rR_A

Substituting  135 N for F_r (Force acting on sprocket),\frac{8.7cm}{2} * \frac{1m}{100cm} = 0.0435m for R_B (radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now

                     \tau = F (0.0435) - 135 (0.33)

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of \alpha  = 3.70 rad/s^2 and this torque can also be represented mathematically as

                   \tau = \alpha I

Now equating the two equation for torque

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                     F = \frac{\alpha I + (135*0.33) }{0.0435}

Substituting values

                  F = \frac{(3.70 * 0.207)  + (135*0.33)}{0.0435}

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