Answer:
y=-2x+8
Step-by-step explanation:
y-y1=m(x-x1)
y-4=-2(x-2)
y-4=-2x+4
y=-2x+4+4
y=-2x+8
x + 3, x > -3 is the piece which will be included in the given function f(x) = [ x + 3 ]. This can be obtained by removing modulus and finding the value for x.
<h3>Which piece will the function include?</h3>
Given that,
f(x) = [ x + 3 ] which is an absolute value function.
Therefore,
| x+3 | > 0
By removing the modulus,
x+3 > 0
x > - 3
Hence x + 3, x > -3 is the piece which will be included in the given function f(x) = [ x + 3 ].
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Consider this absolute value function.
f(x) = [ x + 3 ]
If function f is written as a piecewise function, which piece will it include?
A. x + 3, x > 3
B. x + 3, x > -3
C. -x + 3, x < -3
D. -x - 3, x < 3
1.12x9.2 is equal to 10.30!!! So the result is $10.30
Answer:
x^2 + 18x + 76 + 5 = 0 + 5
Step-by-step explanation:
The first step is to determine the constant that is needed to be able to write the expression in the desired form. That constant is the square of half the x-term coefficient: (18/2)^2 = 9^2 = 81.
The constant that is present is 76, which is 5 fewer than the needed constant, so the "first step" is to add 5 to both sides of the equation:
x^2 + 18x + 76 + 5 = 0 + 5
Then the next step would be to write the left side as a square:
(x +9)^2 = 5 . . . . . . . p = -9; q= 5
It is 5 1/9 after being simplified
