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allsm [11]
2 years ago
6

At left A red ball in a box with arrows pointing away from the ball in all directions. In the middle, a blue ball in a box with

arrows pointing toward the ball from all directions. At right, a grey ball in a box. Which object represents a negatively charged particle? Which object represents a positively charged molecule? Which object represents an uncharged molecule? Which object will not move when in an electric field?
Physics
2 answers:
user100 [1]2 years ago
8 0

Answer: The answers are, 1) B. 2) A.  3) C.   4) C.

here is the proof maybe u will understand it more than the numbers and letters lm.ao

Explanation:

MAVERICK [17]2 years ago
6 0

Answer:

first one is b 2nd one is a 3rd is c and the 4th one is c also

Explanation: have a nice day

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The force between two very small charged bodies is found to be F. If the distance between them is tripled without altering their
SpyIntel [72]

Answer:

if the old force is F, the new force is F/9

Explanation:

Recall that the Coulomb force between to charges is inversely proportional to the square of the distance between the charges.

Therefore, if the original distance "d" changes now to be "3d" (tripled), the denominator of the force expression will change from:

d^2 \,\,\, to \,\,\,(3d)^2 = 9\,d^2

thus reducing the original force by a factor 1/9

So if the old force is F, the new force is F/9

6 0
3 years ago
7. A ball of mass m makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.450 its
emmasim [6.3K]

Answer:

mass of the second ball is 0.379m

Explanation:

Given;

mass of first ball = m

let initial velocity of first ball = u₁

let final velocity of first ball  = v₁ = 0.45u₁

let the mass of the second ball = m₂

initial velocity of the second ball, u₂ = 0

let the final velocity of the second ball = v₂

Apply the principle of conservation of linear momentum;

mu₁ + m₂u₂ = mv₁ + m₂v₂

mu₁  +  0  = 0.45u₁m + m₂v₂

mu₁  = 0.45u₁m + m₂v₂ -------- equation (i)

Velocity for elastic collision in one dimension;

u₁ + v₁ = u₂ + v₂

u₁ + 0.45u₁ = 0 + v₂

1.45u₁ = v₂ (final velocity of the second ball)

Substitute in v₂ into equation (i)

mu₁  = 0.45u₁m + m₂(1.45u₁)

mu₁ = 0.45u₁m + 1.45m₂u₁

mu₁ - 0.45u₁m = 1.45m₂u₁

0.55mu₁ = 1.45m₂u₁

divide both sides by u₁

0.55m = 1.45m₂

m₂ = 0.55m / 1.45

m₂ = 0.379m

Therefore, mass of the second ball is 0.379m (where m is mass of the first ball)

6 0
3 years ago
It took 3 seconds for an object that was thrown up with velocity vo from
otez555 [7]

Answer:

ik u got it bc this was 2 weeks ago

Explanation:

but yes and yuea

5 0
3 years ago
HELPPP PLEASE !!!!!!!
vlabodo [156]

Explanation:

a) d = ½.a.t²

200 = ½(4)t²

200 = 2t²

t² = 200/2

t² = 100

t =√100 = 10 s

b) Vt = a. t

= 4(10)

= 40 m/s

c) V av. = d/t = 200/10 = 20m/s

6 0
2 years ago
8. An airplane is flying at 200 m/s when it touches the ground at the airport. It has a constant negative acceleration, and slow
Temka [501]

Answer:

Explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²

8 0
3 years ago
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