Explanation:
90 kmhr—1 x 1000/3600 = 25ms—1
U = 0 ms—1
V = 25ms—1
t = 10 s
a = ?
a = V - U/t
a = 25 - 0/10
a = 25/10
a = 2.5 ms—1
Answer:
At the closest point
Explanation:
We can simply answer this question by applying Kepler's 2nd law of planetary motion.
It states that:
"A line connecting the center of the Sun to any other object orbiting around it (e.g. a comet) sweeps out equal areas in equal time intervals"
In this problem, we have a comet orbiting around the Sun:
- Its closest distance from the Sun is 0.6 AU
- Its farthest distance from the Sun is 35 AU
In order for Kepler's 2nd law to be valid, the line connecting the center of the Sun to the comet must move slower when the comet is farther away (because the area swept out is proportional to the product of the distance and of the velocity: 
, therefore if r is larger, then v (velocity) must be lower).
On the other hand, when the the comet is closer to the Sun the line must move faster (, if r is smaller, v must be higher). Therefore, the comet's orbital velocity will be the largest at the closest distance to the Sun, 0.6 A.
Answer:
You will be able to tell whether the unknown cell is from an animal or from a plant through the knowledge of difference between plants and animal cells.
Explanation:
A cell can be defined as the simplest bit of living matter which exhibits a variety of shapes and sizes and that can exist independently.
When a slide of an unknown cell is studied under a microscope, different cell structures would be observed which would be used to conclude if the cell on the slide is a plant or animal cell.
The following features are observed in a plant cell:
--> cellulose cell wall is present
--> Chloroplast is present
--> A large central vacuole is present
--> Centriole is absent
The following features are observed in animal cell:
--> Cellulose cell wall is absent
--> Chloroplast is absent
--> Small vacuoles is present
--> Centriole is present
The difference between a plant and an animal cell can be seen from the features above and a clear knowledge of this will help the student tell whether the unknown cell is from an animal or from a plant.
Explanation:
The total energy of an aircraft flying in the atmosphere can be calculated using equation 1. [2]
E = ½ m v2 + mgh
A Boeing 737-300 has a maximum takeoff weight of 5.65 × 104 kg, a cruise altitude of h = 10,195 m, and cruise speed of 221 m/sec. Inserting these numbers into the above equation, we obtain 7.03 GJ for the energy at cruise conditions. [3] However, the engines mounted onto the wings of the plane are required to provide additional energy per time, power, in order to keep the aircraft flying at a constant altitude and speed
Work is the energy needed to apply a force to move an object a particular distance, where force is parallel to the displacement. Power is the rate at which that work is done.
