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a_sh-v [17]
4 years ago
12

How many electrons must be transferred from an object to produce a charge of 1.15 c? (express your answer to three significant f

igures.)?
Physics
1 answer:
Darina [25.2K]4 years ago
6 0
<span>To produce a charge of 1.15 Coulombs in an object, we need to transfer = 1.15/(charge on an electron) number of electrons

   As we know that, total charge on an electron = 1.60217662 Ă— 10 ^-19 coulombs
    Hence, number of electrons required to move = 1.15/(1.60217662 Ă— 10 ^-19) = 0.71777 x 10^19 electrons, i.e. 7.17 x 10^18 electrons upto 3 significant figures</span>
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A basketball player jumped straight up to grab a rebound. If she was in the air for 0.80 second, how high did she jump?
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-- She went up for 0.4 sec and down for 0.4 sec.

-- The vertical distance traveled in gravity during ' t ' seconds is

                   D  =  (1/2)  x  (g)  x  (t)²

                       = (1/2) (9.8 m/s²) (0.4 sec)²

                       =    (4.9 m/s²)  x  (0.16 s²)

                       =      0.784 meter        ( B )
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3 years ago
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A man is running with a tennis ball in his hand. On his left is a bull's-eye target painted
san4es73 [151]

Answer: Horizontal force.

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3 years ago
The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o
WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which \mu k = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant \theta = 30^{o}.

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

           \sum F_{y} = 0

         N - W = 0

           N = W

or,      N = 75 lb

Again, equilibrium condition in the vertical direction is  as follows.

        \sum F_{x} = 0

       T_{2} - F_{k} = 0

         T_{2} = \mu_{k} N

                  = 0.4 \times 75 lb

                  = 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

         \sum F_{x} = 0

       T Cos (30^{o}) + T Cos (30^{o}) = T_{2}

          2T Cos (30^{o}) = T_{2}

    or,             T = \frac{T_{2}}{2 Cos (30^{o})}

                        = \frac{30}{2 Cos (30^{o})}

                        = \frac{30}{1.732}

                        = 17.32 lb

Now, we will calculate the output power of the motor as follows.

             P = Tv

                = 17.32 lb \times 6

                = 103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}

                = 0.189 hp

or,             = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0
3 years ago
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I don't know the answer but I do know this 
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A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the
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Answer:

Explanation:

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4 )  magnitude of the force of gravity on each person

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= 71 x 9.8

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