Answer: The efficiency Shelly does is 87.5%.
(70J/80J) x 100% = 87.5%
Answer 2: Gravitational potential energy would be considered an object 10 meters above the ground.
Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the amplitude of the wave
Using formula of velocity
Put the value into the formula
Hence, The amplitude of the wave is 0.02 m.
Answer:
λ= 5.24 × 10 ⁻² nC/cm
Explanation:
Given:
distance r = 4.10 cm = 0.041 m
Electric field intensity E = 2300 N/C
K = 9 x 10 ⁹ Nm²/C
To find λ = linear charge density = ?
Sol:
we know that E= 2Kλ / r
⇒ λ = -E r/2K (-ve sign show the direction toward the wire)
λ = (- 2300 N/C × 0.041 m) / 2 × 9 x 10 ⁹ Nm²/C
λ = 5.24 × 10 ⁻⁹ C/m
λ = 5.24 nC/m = 5.24 nC/100 cm
λ= 5.24 × 10 ⁻² nC/cm
Answer:
120.03 points on it and its 1234.4KG on the earth
<span>The answer is C. A scale would include a series of eight notes, where the first and seventh notes have the same letter.
Just took the test. Got 100%
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