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Triss [41]
1 year ago
8

4. A banking system provides users with several services:

Engineering
1 answer:
VLD [36.1K]1 year ago
4 0

A diagram showing a use case diagrams for these requirements is given in the image attached.

<h3>What is system Case diagram?</h3>

A use case diagram is known to be a kind of graphical illustration of a users in terms of their various possible association or interactions within any given system.

A use case diagram in banking can be used to prepare, depict and also to know all the functional requirements of the banking system.

Therefore, Give the use case specification for the banking system services and paying a bill online is given in the image attached.

Learn  more about Case diagram from

brainly.com/question/12975184

#SPJ1

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The Stokes-Oseen formula for drag force F on a sphere of diameter D in a fluid stream of low velocity V, density p and viscosity
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Answer:

\frac{ML}{T^2}=\frac{ML}{T^2}

Hence it is proved that Stokes-Oseen formula is dimensionally homogenous.

Explanation:

For equation to be dimensionally homogeneous both side of the equation must have same dimensions.

For given Equation:

F= Force, μ= viscosity, D = Diameter, V = velocity, ρ= Density

Dimensions:

F=\frac{ML}{T^2}

\mu=\frac{M}{LT}

D=L\\\\V=\frac{L}{T}\\ \\\rho=\frac{M}{L^3}

Constants= 1

Now According to equation:

\frac{ML}{T^2}=[\frac{M}{LT}][L] [\frac{L}{T}] + [\frac{M}{L^3}][\frac{L^2}{T^2}][L^2]

Simplifying above equation, we will get:

\frac{ML}{T^2}=2*\frac{ML}{T^2}

Ignore "2" as it is constant with no dimensions. Now:

\frac{ML}{T^2}=\frac{ML}{T^2}

Hence it is proved that Stokes-Oseen formula  is  dimensionally homogenous.

5 0
2 years ago
A developer is having a single-lane raceway constructed with a 100 mph design speed. A curveon the raceway has a radius of 1000-
Hoochie [10]

Answer:

(a) 36+45.00

(b) 24+65.00  

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2 years ago
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Kelly, the GearUp CEO, calls you into her office and says that she feels that her management team and the GearUp company as a wh
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2 years ago
A well insulated turbine operates at steady state. Steam enters the turbine at 4 MPa with a specific enthalpy of 3015.4 kJ/kg an
Anarel [89]

Answer:

power developed by the turbine = 6927.415 kW

Explanation:

given data

pressure = 4 MPa

specific enthalpy h1 = 3015.4 kJ/kg

velocity v1 = 10 m/s

pressure = 0.07 MPa

specific enthalpy h2 = 2431.7 kJ/kg

velocity v2 = 90 m/s

mass flow rate = 11.95 kg/s

solution

we apply here  thermodynamic equation that

energy equation that is

h1 + \frac{v1}{2}  + q = h2 + \frac{v2}{2}  + w

put here value with

turbine is insulated so q = 0

so here

3015.4 *1000 + \frac{10^2}{2}  =  2431.7 * 1000 + \frac{90^2}{2}  + w

solve we get

w = 579700 J/kg = 579.7 kJ/kg

and

W = mass flow rate × w

W = 11.95 × 579.7

W = 6927.415 kW

power developed by the turbine = 6927.415 kW

7 0
2 years ago
Which of the following is not a part of the Gross Domestic Product?
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Answer:

is there any answer choices??

Explanation:

i néed to know

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