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puteri [66]
3 years ago
7

Explain how density differs from volume.

Physics
1 answer:
katrin2010 [14]3 years ago
6 0
Density is the relation between mass and the volume that it occupies.

volume is just a property defined by the space that something occupies.


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Light is shining perpendicularly on the surface of the earth with an intensity of 680 W/m^2. Assuming that all the photons in th
andrew11 [14]

Answer:

3.066×10^21  photons/(s.m^2)

Explanation:

The power per area is:

Power/A = (# of photons /t /A)×(energy / photon)

E/photons = h×c/(λ)

photons /t /A = (Power/A)×λ /(h×c)  

photons /t /A = (P/A)×λ/(hc)

photons /t /A = (680)×(678×10^-9)/(6.63×10^-34)×(3×10^-8)

                      = 3.066×10^21

Therefore, the number of photons per second per square meter 3.066×10^21  photons/(s.m^2).

4 0
3 years ago
How many meters are there in 666 miles? (1 mi = 1609 m)
ki77a [65]

Answer:

1071823.104 Meters

Explanation:

5 0
3 years ago
Do heavier objects fall more slowly than lighter objects?
aksik [14]
Think of it like this, gravity has to pull harder on the heavier object to make them fall at the same rate , but doesn't have to pull as hard for the lighter object , thus is why sometimes heavier objects fall faster then lighter ones
8 0
3 years ago
A diffraction grating is illuminated simultaneously with red light of wavelength 670 nm and light of an unknown wavelength. The
marusya05 [52]

Answer:

dsin∅ = m× λ

so, dsin∅red = 3(670nm)

also, dsin∅? =5λ?

however ,if they overlap then dsin∅red = dsin∅?

3(670nm) /5 =402nm

∴λ = 402nm

Explanation:

4 0
3 years ago
An unknown material, m1 = 0.49 kg, at a temperature of T1 = 92 degrees C is added to a Dewer (an insulated container) which cont
erastova [34]

Answer:

c_u=1540.5J/kg^{\circ}K

Explanation:

We know that heat relates to mass, specific heat and variation of temperature experimented because of this heat through the equation Q=mc\Delta T=mc(T_f-T_i). The heat released by the unknown material is absorbed by water, so we have Q_u=-Q_w, and we can write:

m_uc_u(T_{uf}-T_{ui})=-m_wc_w(T_{wf}-T_{wi})

Since thermal equilibrium is reached we know that T_{cf}=T_{wf}=T_f=31^{\circ}C=304^{\circ}K, where we have added 273^{\circ} to convert the temperature from Celsius to Kelvin, as <em>we must do</em>. Since we want the specific heat of the unknown material, we do:

c_u=-\frac{m_wc_w(T_f-T_{wi})}{m_u(T_f-T_{ui})}

Which for our values is:

c_u=-\frac{(1.1kg)(4186J/kg^{\circ}K)((304^{\circ}K)-(294^{\circ}K))}{(0.49kg)((304^{\circ}K)-(365^{\circ}K))}=1540.5J/kg^{\circ}K

3 0
3 years ago
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