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morpeh [17]
2 years ago
6

How can the spectrum of a star be used to determine the composition of a star?

Physics
1 answer:
Setler79 [48]2 years ago
7 0

Answer:

The spectrum of a star can be used to determine its composition by observing the spectrum lines that gains by the diffraction pattern of different light wavelengths and the Fraunhofer lines observed through spectroscope.

Explanation:

As far as we all have seen the attractive rainbow colours in the moist daylight, we know the seven colours that are visible to our eyes. what we see is actually the spectrum of the white light emitted by the light sources or we can say the Sun which is a star.

With the invention of spectroscopy, it gets feasible for us to evaluate the different spectrum displayed by the prism and diffraction grating. The light emitted from the source or stars as we can say in this discussion, are spread into its constituent visual wavelengths that is known as the Spectrum. This method is known as spectroscopy.

With the help of spectrometer, astronomers can easily observe the wavelengths, their properties and eventually judge the elements through which the lights is emitted.

For example, in case of Sun, it is composed of Hydrogen (87%), Helium (10%), and other elements (3%). With the estimation of the strength of various spectral lines, it gets possible to find various elements and their amount with which they are composed such as the Sun is mostly made of the Hydrogen and helium gas.

in this way, we can easily observe the elements according to the spectral pattern studied through spectrometer and compare them with the elements in the periodic table. Hence, we can determine the composition of stars.

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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
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Answer:

Explanation:

All the displacement will be converted into vector, considering east as x axis and north as y axis.

5.3 km north

D = 5.3 j

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D₁= 8.3 cos 50 i + 8.3 sin 50 j.

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Let D₂ be the displacement which when added to D₁ gives the required displacement D

D₁ + D₂ = D

5.33 i + 6.36 j + D₂ = 5.3 j

D₂ = 5.3 j - 5.33i - 6.36j

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magnitude of D₂

D₂²= 5.33² + 1.06²

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Angle θ

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2 years ago
Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

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We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

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3 years ago
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