Answer:
Angiosperms are vascular plants bearing the seeds in fruits or mature ovaries whilst gymnosperms are other types of the plant which bears the seeds directly on the sporophylls but without any cover.
Explanation:
Examples of gymnosperms include cypress,pine, redwood, spruce and ginkgo.
Examples of angiosperms include apple, banana,peach, cherry and orange.
Also, angiosperms are seeds producing flowering plants whose seeds are enclosed within an ovary.
Gymnosperms are also seeds producing non flowering plants whose seeds are unenclosed.
Hope it helps.
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I thinking the answer was for some genes, both alleles express together. Others combine to give an average phenotype....
The best and the correct answer among the choices provided by the question is the second choice.
Temporal isolation could be the mechanism that <span>might keep Rana aurora and Rana boylii from mating.</span>
I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
Answer: 1/16, or approximately 6.25% (see explanation below)
Explanation:
Answering this question requires two steps.
First, we need to figure out the probability that this couple will have a child with albinism in the first place. We know the following:
- Both parents are unaffected.
- The couple has already had one affected child.
- Albinism follows an autosomal recessive inheritance pattern.
Let ( M = normal gene ) and ( m = mutated gene ). Since the condition is recessive, the affected child can be assumed to have a “mm” genotype. Barring the possibility of a de novo mutation (which are assumed to be rare), the affected child must have inherited one ”m” allele from each parent. Since both of them are unaffected, however, we can assume that they are both carriers (genotype “Mm”). In conclusion, 1/4 of their offspring (25%) <em>for any given pregnancy</em> may be expected to have albinism. See the resulting Punnett square:
<u> | M | m </u>
<u>M | MM | Mm </u>
<u>m | Mm | mm </u>
Note that the question asks about the probability that not one but two consecutive births result in affected children. Since it can be assumed that both events are independent (meaning: the outcome of a pregnancy does not influence the outcome of following ones), we may apply the rule of multiplication for probabilities. The final answer is therefore 1/4 * 1/4 = 1/16.
