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saw5 [17]
3 years ago
14

If the magnets are brought close together, they will

Physics
2 answers:
murzikaleks [220]3 years ago
7 0

It depends on which side. Opposites attract, so north and south would attract to each other and collide, while north and north or south and south would go away from eachother.

lisabon 2012 [21]3 years ago
5 0

opposites attract and if theyre the same they go away from eachother

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A fluid is
svetoff [14.1K]
C) a substance that flows
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3 years ago
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What is angular frequency​
Firlakuza [10]
Measures angular displacement per unit time.
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A bear scratches his claws on a big pine tree. Does the bear do work on the tree? why or why not?
Ganezh [65]

Answer:

See the explanation below.

Explanation:

Work in physics is defined as the product of force by the distance that the body travels in the direction of the force.

It can be represented by means of the following equation.

W=F*d

where:

W = work [J]

F = force [N]

d = distance [m]

In the given example the work is zero since the tree does not move, therefore the bear exerts a force on the tree. But there is no talk of movement of the tree, therefore the work is zero.

8 0
3 years ago
The offspring resulting from sexual reproduction are exactly like their parents.
sammy [17]

Answer:

false

Explanation:

As both parents contribute half of the new organism's genetic material, the offspring will have traits of both parents, but will not be exactly like either parent

3 0
3 years ago
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1. The strength coefficient and strain-hardening exponent of brass are 100,000 lb/in2 and 0.35 respectively. A cylindrical speci
aleksandr82 [10.1K]

To solve this problem we will apply the concepts of strain, flow stress and average flow stress to find the required data. We will start by calculating the Strain which is the logarithmic relationship between the longitudinal change. Later we will find the flow stress through the strength coefficient, the strain and the strain-hardening exponent. Finally with the found values it will be possible to find the average flow stress,

Now the strain is calculated with the logaritmic relation of the lengths.

\epsilon = ln(\frac{1.5}{3.0})

\epsilon = ln(0.5)

\epsilon = 0.69315in/in

With this value we can calculate the flow stress,

Y_f = K\epsilon^n

Here,

K = Strneght coefficient

n = Strainhardening exponent of brass

Y_f = (100000)(0.69315)^{0.35}

Y_f = 87961lb/in^2

Finally the average flow stress will be given under the relation:

\bar{Y_f} = \frac{K\epsilon^n}{1+n}

\bar{Y_f} = \frac{(100000)(0.69315)^{0.35}}{1.35}

\bar{Y_f} = 65156lb/in^2

6 0
3 years ago
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