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e-lub [12.9K]
3 years ago
15

Identify the techniques used to try to locate extra solar (exo) planets

Physics
2 answers:
attashe74 [19]3 years ago
8 0

Answer:

the doppler technique

Explanation:

The doppler technique was  an indirect method for finding extrasolar planets and brown dwarfs from radial-velocity measurements using observation of Doppler shifts in the spectrum of the planet's parent star.

antiseptic1488 [7]3 years ago
5 0

Answer:

A Transits

B Doppler technique

Explanation:

The techniques used for the location of extra solar planets are both transit method and the Doppler technique. Extra solar planets are those that orbit a star other than the Sun of our solar system.

Transit method uses the method of measuring light curve from the stars and the reduction of the brightness over time is noted. This is an indirect method.

Doppler technique is a much more  reliable method  to discover exoplanets. It is also called wobble method. This is much more reliable to detect exoplanets. When there is no exoplanet for a given star, the Doppler shift pattern does not change. If exoplanet exists, it changes.

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The images output from your new color laser printer seem to be a little too blue. What can you do to fix this?
Svetradugi [14.3K]

Answer:

The images output from your new color laser printer seem to be a little too blue. to fix this problem we need to calibrate the printer.

Explanation:

This can be done by opening the toolbox, clicking in the device setting folder their you get print quality page click on it. Under the print quality option click on the calibrate next to calibrate now. Then click OK unless when the 'your request has been sent to the device' appears on the screen. When the calibration ends again try printing. calibrating is useful for managing the proper alignment of the inkjet cartridge nozzle to the paper and each other, without proper calibration the print quality deteriorates.

3 0
3 years ago
A 2.00-kg block of ice is moving on a frictionless horizontal surface. At t = 0 the block is moving to the right with a velocity
enyata [817]

Answer:

Explanation:

a )

We shall apply the concept of impulse .

Impulse = force x time = change in momentum

= 5 x 4 = 2 ( V - 3 )  , where V is final velocity of the object

20 = 2V - 6

V = 13 m /s

b )

Impulse applied = - 7 x 4 = - 28 kg m/s ( negative as direction of force is opposite motion )

If v be the final velocity

2 x 3 - 28 = 2 v  ( initial momentum - change in momentum = final momentum )

- 22 = 2v

v = - 11 m /s

object will move with 11 m /s in opposite direction .

4 0
3 years ago
Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0
DENIUS [597]

Answer:

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

Explanation:

We have given mass m = 1.7 kg

radius of the circle r = 0.48 mF=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N

Kinetic energy is given 14 J

Kinetic energy is equal to KE=\frac{1}{2}mv^2

So \frac{1}{2}\times 1.7\times v^2=14

v^2=16.47

v = 4.05 m/sec

Centripetal force is equal to F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N

So tension in the string will be equal to 58.33 N ( this will be the strength of the string )

3 0
3 years ago
a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?
zhenek [66]
According to Hooke's law, Force = spring constant x displacement of the spring. Spring constant = Force/displacement in spring = 45/0.14 = 321.42 N/m. Hope this helps!
3 0
3 years ago
Read 2 more answers
How to find acceleration without final velocity?
Andrews [41]
Acceleration is the rate of change of a the velocity of an object that is moving. This value is a result of all the forces that is acting on an object which is described by Newton's second law of motion. Calculation of such is straightforward, if we are given the final velocity, the initial velocity and the total time interval. We can just use the kinematic equations. However, if we are not given the final velocity, it would not be possible to use the kinematic equations. One possible to calculate this value would be by generating an equation of distance with respect to time and getting the second derivative of the equation.
7 0
3 years ago
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