Question

Argon in the amount of 0.6 kg fills a 0.05 m3 piston cylinder device at 550 kPa. The piston is now moved by changing the weights until the volume is twice its original size. During this process, Iron’s temperature is maintained constant. Determine the final pressure in the device.

Answer 1

Answer:

The final pressure in the device is 275 kPa.

Explanation:

Given that,

Amount of argon = 0.6 kg

Initial volume = 0.05 m³

Pressure = 550 kPa

Final volume = 2 initial volume

Temperature is constant.

We need to calculate the final pressure

Using ideal gas

$P_{1}V_{1}=RT_{1}$

$P_{1}V_{1}=RT_{2}$

Here, Temperature is constant

So, from equation (I) and equation (II)

$P_{1}V_{1}=P_{2}V_{2}$

$P_{2}=\dfrac{P_{1}V_{1}}{V_{2}}$

Put the value into the formula

$P_{2}=\dfrac{550\times10^{3}\times0.05}{2\times0.05}$

$P_{2}=275000\ Pa$

$P_{2}=275\ kPa$

Hence, The final pressure in the device is 275 kPa.