The correct answer is - the North Pole only.
During the Ice Age, or rather the glaciation, the continental glaciers originated from the North Pole and started expanding deeper into the continental masses from that starting point. The South Pole can be excluded because doesn't really matter if it is an Ice Age or not it is still frozen, plus Antarctica is surrounded with ocean waters thus the ice cannot expand further.
The glaciers during the Ice Age managed to occupy large portions of North America, coming as south as the northern part of what is now the United States. Also, the northern half of Europe and the northern half of Asia were also covered in ice.
Answer:
a scientist examines the results and answers the lab question- last choice
Explanation :
The heating curve shows how water changes from one state of matter to another based on temperature and the addition or removal of heat over time.
Initially, ice is heated until its temperature reaches and changes to liquid state.
From the attached graph it is clear that until the temperature will rise steadily. Here, the liquid begins to vaporize. Vaporization is the state of matter at which liquid state changes to the gaseous state.
So, E is the point which shows the gaseous state.
Answer:
Required time t=5.8s
Explanation:
Given data
Acceleration a=3.08 m/s²
Speed v=29.4 m/s
Required
How much time t is required
Solution
As the train passes through the crossing its motion is described by:
Substitute the given values
So
So time required can be calculated by:
Required time t=5.8s
Answer: 5.52 *10^-6J
Explanation: In order to explain this problem we have to take into account the expression for the stored energy in a capacitor which is given by:
U=Q^2/2*C=2.76*10^-6 J ( initial stored energy)
We also know that C=Q/V=221*10^-9/25 V=8.84*10^-9 F
When the separation between the plates is increased 3 times, the capacitanve decrease a factor 1/3 then the stored energy is:
U=Q^2/(2*C/3)= 3*Q^2/(2*C)=3*(221*10^-9)^2/2*8.84*10^-9=8.28*10^-6J ( final stored energy)
The change in the stored energy is : 8.28*10^-6J-2.76*10^-6 J=
=5.52 *10^-6 J