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STALIN [3.7K]
3 years ago
7

How does flame spread over liquid depend on the flash point?

Chemistry
1 answer:
zvonat [6]3 years ago
6 0
If the liquid is at or above its flash point, the flame spread rate is fast, and the entire pool is engulfed within seconds. ... As the liquid temperature decreases, flame radiation must both heat the liquid to the flash point temperature and supply the heat of vaporization.
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Consider the temperature versus time graph below.
Brrunno [24]

Answer : At 120°C

Explanation : At 120°C temperature the boiling point of this substance is observed in the given graph.

As per the definition of the boiling point, <em>"It is the temperature at which the vapour pressure of the given substance becomes equal to the standard surrounding atmospheric pressure"</em>

Here, in this graph, it is clearly seen at 120°C where the substance raises to the high temperature and remains stable for certain period of time and then again slightly increases.

7 0
3 years ago
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I have a chemistry question that I am needing help on please?​
aliina [53]
What country and grade are you?
Please tell me! I’m going to help you
8 0
3 years ago
A gas with a volume of 4.0 L at 90.0 kPa expands until the pressure drops to 20.0 kPa. What is its new volume if the temperature
Flauer [41]
<span>You are trying to find V2, the formula is V2</span>= <span><span>P1 / </span><span>P2 </span></span>⋅ V<span>1
</span><span>input your numbers, V2</span>= <span><span>90.0kPa / </span><span>20.0kPa </span></span>⋅ 4.0 L to get 18 L
4 0
3 years ago
Explain why Cl, is an element and NOT a compound.
GarryVolchara [31]

Answer:

Cl is not a compound because compounds are made up of atoms from MORE than one element. Since Cl is a singular element is cannot be a compound

Explanation:

Just think of it as Compounds are always more than one elements are always Single

4 0
2 years ago
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Given that ΔH = −571.6 kJ/mol for the reaction 2 H2(g) + O2(g) → 2 H2O(l), calculate ΔH for these reactions. (a) 2 H2O(l) → 2 H2
pashok25 [27]

Answer : The value of \Delta H for the reaction is +571.6 kJ/mole.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)     \Delta H_1=-571.6kJ/mole

Now we have to determine the value of \Delta H for the following reaction i.e,

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)    \Delta H_2=?

According to the Hess’s law, if we reverse the reaction then the sign of \Delta H change.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=-(-571.6kJ/mole)

\Delta H_2=+571.6kJ/mole

Hence, the value of \Delta H for the reaction is +571.6 kJ/mole.

6 0
3 years ago
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