Answer:
The time is 2.8 ms.
Explanation:
Given that,
Capacitor = 0.12 μF
Resistance = 10 kohm
Voltage = 12 V
Charge Q = 0.9 Q₀
We need to calculate the time constant
Using formula of time constant
Put the value into the formula
We need to calculate the time
Using formula of time
Put the value into the formula
Hence, The time is 2.8 ms.
Answer:Twice
Explanation:
It is given that car is raised on a lift with respect to ground.
Suppose car is raised by a height of h m from ground having mass m so gain in Potential Energy by car is
Gain in
Now if it were raised twice as high,i.e. 2 h height from ground then gain in Gravitational Potential Energy
It is clear that
Thus in second case gain in Potential Energy is twice as compared to first case
Answer:
Explanation:
Capacity of a parallel plate capacitor C = ε₀ A/ d
ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.
C =( 8.85 X10⁻¹² X 27 X 10⁻⁴ ) / 3 X 10⁻³
= 79.65 X 10⁻¹³ F.
potential diff between plate = Charge / capacity
= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³
= 601 V
Electric field = V/d
= 601 / 3 x 10⁻³
= 2 x 10⁵ N/C
Force on proton
= charge x electric field
1.6 x 10⁻¹⁹ x 2 x 10⁵
= 3.2 x 10⁻¹⁴
Acceleration a = force / mass
= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷
= 1.9 x 10¹³ m s⁻²
Distance travelled by proton = 3 x 10⁻³
3 x 10⁻³ = 1/2 a t²
t =
t = 1.77 x 10⁻⁸ s