Answer:
B. The object's volume
Explanation:
When an object is immersed in a fluid, it experiences an upward force which is called buoyant force. The magnitude of the buoyant force is given by:
where
is the density of the fluid in which the object is immersed
is the volume of the fluid displaced by the object
is the acceleration due to gravity
When the object is totally immersed in the fluid, corresponds to the volume of the object; when the object is only partially immersed, corresponds only to the volume of the part of the object immersed.
From the formula, we see that the greatest buoyant force is experienced by the object when it is fully immersed. Moreover, we see that the buoyant force depends only on one property of the object: its volume. Therefore, the correct choice is
B. The object's volume
To solve letter a:
d1 = 85t1 = 16 km,
85t1 = 16,
t1 = 16 / 85 = 0.1882 h = 11.29 min.
d2 = 115t2 = 16 km,
115t2 = 16,
t2 = 16 / 115 = 0.139 h = 8.35 min.
t1 - t2 = 11.29 - 8.35 = 2.94 min.
Car #2 arrives 2.94 minutes sooner.
To solve letter b:
15 min = 1/4 h = 0.25 h.
d1 = d2,
115t = 85(t + 0.25),
115t = 85t + 21.25,
115t - 85t = 21.25,
30t = 21.25,
t = 21.25 / 30 = 0.71 h,
d = 115 * 0.71 = 81.65 km.
Answer:
2 J
Explanation:
A charged capacitor of capacitance 
with energy of 7.54 J, is connected in parallel with another capacitor 
, so the charge is equally distributed between them.
(a) The energy stored in the capacitor before it being connected to the other capacitor is:
The energy stored in the electric field is the sum of the energies of the two capacitors:
since the charge equally distributed, 
= 
= 
. and since they are connected in parallel the potential difference on both of them is the same
:
hence,
Answer:
Explanation:
Speed and medium are properties of a wave which is in common within an area of the spectrum of visible light. i.e;
Their medium of propagation
They both travel at the same speed ( speed of light )
The properties mentioned above are properties that define that wave is found within an area spectrum for visible light.
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Answer
given,
D = 50 mm = 0.05 m
d = 10 mm = 0.01 m
Force to compress the spring
F = 3160 N
stress correction factor from stress correction curve is equal to 1.1
now, calculation of corrected stress
= 442.6 Mpa
The tensile strength of the steel material of ASTM A229 is equal to 1300 Mpa
now,
since corrected stress is less than the 
hence, spring will return to its original shape.
