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4 years ago

A student placed a ladder up against a wall as shown below. The normal force applied by the wall in the ladder will be directed:

Physics

1 answer:

solmaris [256]4 years ago

6 0

The normal force is always perpendicular to the surface. So it would be straight to the left of the wall

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Two simple pendulums are in two different places. The length of the second pendulum is 0.4 times the length of the first pendulu

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$\sqrt{\frac{4}{9}}$

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The frequency of a simple pendulum is given by:

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So the frequency of the second pendulum is

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$\frac{f_1}{f_2}=\frac{\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}}{\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}}=\sqrt{\frac{0.4}{0.9}}=\sqrt{\frac{4}{9}}$

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