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sleet_krkn [62]
3 years ago
8

Which of the following were utilized in romanesque architecture?

Physics
2 answers:
PolarNik [594]3 years ago
6 0
Towers were used in Romanesque Architecture
LiRa [457]3 years ago
5 0
Hey there,
The answer is D, All of the above
Arches, Vaults and Towers were utilized in Romanesque architecture
Hope this helps :))

~Top
You might be interested in
Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de
inessss [21]

Answer:

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

\Delta \theta = \omega \cdot \Delta t

\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

4 0
3 years ago
A 91-kg astronaut and a 1300-kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, givi
WARRIOR [948]

Answer:

18.2145 meters

Explanation:

Using the conservation of momentum, we have that:

m1v1 + m2v2 = m1'v1' + m2'v2'

m1 = m1' is the mass of the astronaut, m2=m2' is the mass of the satellite, v1 and v2 are the inicial speed of the astronaut and the satellite (v1 = v2 = 0), and v1' and v2' are the final speed of the astronaut and the satellite. Then we have that:

0 + 0 = 91*v1' + 1300*0.17

v1' = -1300*0.17/91 = -2.4286\ m/s

The negative sign of this speed just indicates the direction the astronaut goes, which is the opposite direction of the satellite.

If the astronaut takes 7.5 seconds to come into contact with the shuttle, their initial distance is:

distance = 2.4286 * 7.5 = 18.2145\ meters

8 0
3 years ago
Velocity is described by __ and time
klasskru [66]

Answer:

direction and time

Explanation:

4 0
3 years ago
Describe the difference between distance, position, and displacement
nata0808 [166]

Answer:

Explanation:

<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>

<em>Displacement is the difference in the object's position from one time to another.</em>

<em>Distance is the total amount the object has traveled in a certain period of time.</em>

<em />

<em>I hope this helps!</em>

<em />

5 0
2 years ago
A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above t
ycow [4]

Answer:

Explanation:

Applied force, F = 18 N

Coefficient of static friction, μs = 0.4

Coefficient of kinetic friction, μs = 0.3

θ = 27°

Let N be the normal reaction of the wall acting on the block and m be the mass of block.

Resolve the components of force F.

As the block is in the horizontal equilibrium, so

F Cos 27° = N

N = 18 Cos 27° = 16.04 N

As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .

The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N   .... (1)

The vertically downward force acting on the block is mg - F Sin 27°

                                                      = mg - 18 Sin 27° = mg - 8.172    ... (2)

Now by equating the forces from equation (1) and (2), we get

mg - 8.172 = 6.42

mg = 14.592

m x 9.8 = 14.592

m = 1.49 kg

Thus, the mass of block is 1.5 kg.  

6 0
3 years ago
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