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3 years ago

9

While looking at bacteria under a microscope you decide to take a break when u return the amount of bacteria has doubled in size

your break probably only took

1 answer:

VikaD [51]3 years ago

4 0

Your break probably only took 20-30 minutes. Bacteria can double every 20-30 minutes. Hope this helped!
~ Sincerely,
Cutenerd1234
XOXO

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Describe a situation in which you exert a force on something and it does not move. Identify the action force and the reaction fo

goldfiish [28.3K]

Answer:

Please find the answer in the explanation.

Explanation:

To describe a situation in which you exert a force on something and it does not move, you need to Identify the action force and the reaction force, the relative size of the forces, and the objects they act on.

The magnitude of the static friction between the object and the ground is larger than the magnitude of the force applied.

The object will not move if the magnitude of the static friction is greater than the magnitude of the force applied.

The action force is the force applied while the reaction force is equal to the frictional force between the object and the ground.

3 0

3 years ago

a uniform electric field E=15 N/C points downwards. A particle with charge q=-0.15 C is placed in the electric field. What is th

Alex17521 [72]

Answer:

2.25 N upwards

Explanation:

Answer:

800 N/C to the right

Explanation:

The equation that relates force on a charge, electric field and charge is

$F=qE$

where

F is the force acting on the charge

q is the charge

E is the electric field

In this problem, we have

$E=15 N/C$ is the electric field

$q=-0.15 C$ is the charge

Substituting into the formula, we find the force

$F=(-0.15 C)(15 N/C)=-2.25 N$

Concerning the direction:

- The electric field and the force have same directions if the charge is positive

- The electric field and the force have opposite directions if the charge is negative

Here the charge is negative, so the electric field has opposite direction to the force: therefore, it must be upwards.

3 0

3 years ago

What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2400 kg car (a large car

makvit [3.9K]

Answer:

Fm= 91.88 N

Explanation:

Pascal principle

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

The pressure is definited like this:

P=F/A

Where:

P: Pressure in pascals (Pa)

F: Force acting in the area (N)

A : Area where the force acts (m²)

Pascal principle

Pm=Ps

Fm/ Am= Fs/ As Formula (1)

Where :

Pm : Pressure on the master piston

Ps : Pressure on the slave piston

Fm : Force on the master piston (N)

Fs: Force on the slave piston ((N)

Am: master piston area (m²)

As: slave piston area (m²)

Area Formula (A)

A= π*R²

R : piston radius

Calculation of the weight of the car (W)

W= m*g= 2400 kg*9.8m/s²= 23520 N

W = Fs

Data

Fs = 23520 N

Dm = 1.5 cm

Ds = 24 cm

Rm = 0.75 cm

Rs = 12 cm

Am = π*Rm² = π*(0.75)²

As = π*Rs² = π*(12)²

Force exerted on the master cylinder

We replace data in the formula (1)

$\frac{F_{m} }{A_{m} } = \frac{F_{s} }{A_{s} }$

$F_{m} = \frac{F_{s}*A_{m} }{A_{s}}$

$F_{m} = \frac{(23520 N)*(\pi *(0.75)^{2})(cm^{2})}{(\pi *(12)^{2})(cm^{2})}$

$F_{m} = (23520 N)*\frac{(0.75)^{2} }{(12)^{2} }$

Fm= 91.88 N

8 0

3 years ago

Aaron rode her bike to his house to play cards he Road for 1.6 hours at 6.5 KMH another 15 minutes at four KMH what was her aver

Kay [80]

Answer:

The average speed during the trip is 6.16 $\frac{km}{hour}$

Explanation:

Speed is a physical quantity that expresses the variation in position of an object and as a function of time. In other words, speed expresses the relationship between the space traveled by an object, the time used for it and its direction.

The speed can be calculated by the expression:

$Speed=\frac{distance}{time}$

Aaron rode his bike home for 1.6 hours at 6.5 km/h and another 15 minutes at 4 km/h. So, the distance in each of the stages can be calculated as, taking into account that 60 minutes= 1 hour:

distance1=speed*time= 6.5 $\frac{km}{h}$ *1.6 hours= 10.4 km

distance2= speed*time= 4 $\frac{km}{h}$ *15 minutes= 4 $\frac{km}{h}$ *0.25 hours= 1 km

So:

total distance= 10.4 km + 1 km= 11.4 km
total time= 1.6 hours + 0.25 hours= 1.85 hours

Then:

$Speed=\frac{11.4 km}{1.85 hours}$

$Speed=6.16\frac{km}{hour}$

<u><em>The average speed during the trip is 6.16 </em></u> $\frac{km}{hour}$ <u><em></em></u>

8 0

3 years ago

A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces

Flura [38]

Answer: (b)

Explanation:

Given

Mass of box $m=17\ kg$

Applied force $F=175\ N$

Friction force $f=-125\ N$

Box travels a distance of $s=15\ m$

time taken $t=5.25\ s$

Net unbalanced force $F_{net}=175-125=50\ N$

Work done by the unbalanced force

$\Rightarrow W=F_{un}\cdot s\\\Rightarrow W=50\times 15\\\Rightarrow W=750\ N$

Power developed by unbalanced force

$\Rightarrow P=\dfrac{W}{t}\\\\\Rightarrow P=\dfrac{750}{5.25}\\\\\Rightarrow P=142.85\approx 1423\ W$

Thus, option (b) is correct.

7 0

3 years ago