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levacccp [35]
3 years ago
8

What is equivalent to 2x-17

Mathematics
1 answer:
Bad White [126]3 years ago
8 0
Get photo math an app just for math it gives u the answers and how to solve it
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18dp - 17b + 17dm - 14dm - 3b + 12dp - 12b
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I’m not sure if the answer is correct but i believe it’s 20dp-32b+3
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Complete this number sentence with the correct symbol.<br><br> 0.90 ___ 0.9 <br> PLZZZZ I NEED HELP
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= because 0.9 and 0.90 are the same
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Review the scenario and the solution. Explain what is wrong with solution and correct the error.
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If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

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3 years ago
Kirk lives in Nebraska, which has a sales tax of 5.5%. He just bought a sewing machine whose full price was $90, but he got 40%
Ksju [112]

Answer:

56.97........................

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