Illluminance is the measurement of photo-metric power. That means, illuminance is the rate of photo-metric flux that is received by a surface per area. It is usually expressed as a unit of W/m^2. Thus, from the choices, the answer we're looking for is illuminance.
F = ma = -kx
a = 9.81 m/s²
k = 3430 N/m
m = 70 kg
x = - ma/ k = 0.2m
Answer:
Explanation:
The balloon would require a time of
t = d/v = 13.5/ (23.6cos38) = 0.7259...s
to travel the horizontal distance.
the vertical position relative to the throw point at that time is
h = 0 + (23.6sin38)(0.7259) + ½(-9.8)(0.7259²)
h = 7.9652...
so as long as the adjacent building is at least 8.0 m higher than the student position, the balloon is in the air for 0.726 s.
If the building is shorter than 8.0 m above the student, the balloon will land on the building roof and will be in the air for a longer period of time
Solution:
In this question we have given,
initial velocity,u = 0
final velocity, v = 1m/s
displacement =.5mm (Because 1mm=.001m)
We have to find
1.acceleration
2. Time
1. we know third equation of motion is given as,
............(1)
Put values of v,u and s in equation (1)
![[tex]s=1^{2} = 0^{2} +2X.0005Xa\\1= .001a\\therefore, a = 1/.001\\ a= 1000m/s^{2}](https://tex.z-dn.net/?f=%5Btex%5Ds%3D1%5E%7B2%7D%20%3D%200%5E%7B2%7D%20%2B2X.0005Xa%5C%5C1%3D%20.001a%5C%5Ctherefore%2C%20a%20%3D%201%2F.001%5C%5C%20a%3D%201000m%2Fs%5E%7B2%7D)
2. We know First equation of motion is given as
......................(2)
put values of v, u and a in equation(2)
Answer:
If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.
Explanation:
