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3 years ago

Which of the following involves an endothermic reaction?

Physics

1 answer:

earnstyle [38]3 years ago

7 0

Answer:

C. Plants converting sunlight into chemical energy.

Explanation:

An "endothermic reaction" is a process whereby energy coming from the surroundings is being absorbed as heat. This activates the reaction to occur. Since it absorbs the heat to start the reaction, then it can be classified as an endothermic reaction.

When plants convert sunlight into chemical energy, it absorbs the sunlight as a light energy on its chlorophyll. This is where photosynthesis occur. This then results to the chlorophyll reacting with the carbon dioxide, water and the energy which results to the production of oxygen and glucose.

So, this explains the answer.

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A 3kg box has 45J of gravitational potential energy, how high is it off the ground?

frez [133]

Answer:

1.53m

Explanation:

Given parameters:

Mass of box = 3kg

Gravitational potential energy = 45J

Unknown

Height of the box = ?

Solution:

To solve this problem;

Gravitational potential energy = mgh

m is the mass

g is the acceleration due to gravity

h is the height

45 = 3 x 9.8 x h

h = 1.53m

7 0

3 years ago

How many outer-orbital electrons are found in an atom of:a) Na?b) P?c) Br?d) I?e) Te?f) Sr?

lys-0071 [83]

Answer:

Na=1
P=5
Br=7
I=7
Te=6
Sr=2

6 0

2 years ago

Rubber is which of the following?

MariettaO [177]

Rubber is an insulator

8 0

3 years ago

A particle of mass m moves under an attractive central force F(r) = -Kr4 with angular momentum L. For what energy will the motio

docker41 [41]

Answer:

Angular velocity is same as frequency of oscillation in this case.

ω = $\sqrt{\frac{7K}{m} }$ x $[\frac{L^{2}}{mK}]^{3/14}$

Explanation:

- write the equation F(r) = -K $r^{4}$ with angular momentum L

- Get the necessary centripetal acceleration with radius r₀ and make r₀ the subject.

- Write the energy of the orbit in relative to r = 0, and solve for "E".

- Find the second derivative of effective potential to calculate the frequency of small radial oscillations. This is the effective spring constant.

- Solve for effective potential

- ω = $\sqrt{\frac{7K}{m} }$ x $[\frac{L^{2}}{mK}]^{3/14}$

3 0

3 years ago

For phyics again , pls !!!

CaHeK987 [17]

Answer: same

Explanation: They both weigh a kilogram and there is no friction

3 0

3 years ago