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Marat540 [252]
2 years ago
11

A 3kg box has 45J of gravitational potential energy, how high is it off the ground?

Physics
1 answer:
frez [133]2 years ago
7 0

Answer:

1.53m

Explanation:

Given parameters:

Mass of box  = 3kg

Gravitational potential energy  = 45J

Unknown

Height of the box  = ?

Solution:

To solve this problem;

 Gravitational potential energy = mgh

m is the mass

g is the acceleration due to gravity

h is the height

            45  = 3 x 9.8 x h

            h  = 1.53m

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3 years ago
________ is the si unit of angular momentum
navik [9.2K]

Answer:

kg m2/s

Explanation:

I think it is :)

4 0
3 years ago
Two lasers are shining on a double slit, with slit separationd.Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelengt
Sophie [7]

Answer:

a) laser 1 has the maximum closest to the central maximum

b) y₂ –y₁ = L 1.66 10⁻²

Explanation:

a), B1, B2)  The expression that describes the constructive interference for a double slit is

            d sin θ = m λ

The pattern is observed on a screen

            tan θ = y / L

Since the angles are very small

           tan θ = sin θ / cos θ = sin θ = y/L

 

           d y / L = m λ  

In this case the laser has a wavelength

           λ ₁ = d/20

We substitute

            d y / L = m d / 20

            m = 1

            y₁ = L / 20

For the laser 2 λ ₂= d / 15

             y₂ = L / 15

When examining the two expressions, laser 1 has the maximum closest to the central maximum

b) the difference between the two patterns is

            y₂- y₁ = L (1/15 - 1/20)

           y₂ –y₁ = L 1.66 10⁻²

C) laser 1 second maximum

          y₁ ’= 2 L / 20

          y₁ ’= L 0.1

Laser 2 third minimum

To have a minimum, the equation must be satisfied

           d sin θ = (m + ½) λ  

           d y / L = (m + ½) λ  

           d y / L = (m + ½) d / 15

           y = L (m +1/2) / 15

           m = 3

           y₂’= L (3 + ½) / 15

           y₂’= L 0.2333

The difference is

           y₁ ’- y₂’ = L (0.1 - 0.2333)

          y₁ ’–y₂’ = L (-0.133)

3 0
3 years ago
A body moves due north with velocity 40 m/s. A force is applied
marshall27 [118]

Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v

p: momentum

m: mass

\Delta v:  change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

\Delta v=v_2-v_1

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

\Delta v =35m/s-40m/s=-5m/s

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

4 0
3 years ago
Unlike velocity, speed is scalar, which means it is described by
slava [35]

Answer:

Magnitude

Explanation:

Scalar quantitys have no direction only a size aka magnitude

6 0
2 years ago
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