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Marat540 [252]
2 years ago
11

A 3kg box has 45J of gravitational potential energy, how high is it off the ground?

Physics
1 answer:
frez [133]2 years ago
7 0

Answer:

1.53m

Explanation:

Given parameters:

Mass of box  = 3kg

Gravitational potential energy  = 45J

Unknown

Height of the box  = ?

Solution:

To solve this problem;

 Gravitational potential energy = mgh

m is the mass

g is the acceleration due to gravity

h is the height

            45  = 3 x 9.8 x h

            h  = 1.53m

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How is desert pavement formed?
mihalych1998 [28]

Desert pavement or commonly called stone or stony pavement is a type of desert surface that is covered with pebbles and stone tight and intertwined. Many of these layers form a type of pavement known as mosaic. When the particles begin to be stacked between different natural agents such as rain, gravity and animals compact the layers and generates a layer that allows the pavement not to erode. Basically runoff and deflation eliminate silt and clay, leaving thicker particles behind.

The correct answer is A.

5 0
2 years ago
What is the wavelength of a sound <br> Wave moving at 340 mls with a Frequency<br> of 256Hz ?
AysviL [449]

Answer: 1.33 metres

Explanation:

Given that:

Wavelength (λ)= ?

Frequency F = 256Hz

Speed of sound wave = 340 m/s

So, apply the formula:

Wavespeed = frequency x wavelength

i.e V = F λ

340m/s = 256Hz x λ

λ = (340m/s ➗ 256Hz)

λ = 1.328 m (Round to the nearest hundredth which is 1.33 m)

Thus, the wavelength of a sound wave is

1.33 metres

6 0
3 years ago
In a p-type semiconductor, p signifying that the number of positive holes in the material has increased, which element could be
Ratling [72]
I think it is aluminum. 
8 0
3 years ago
a stone of mass 7 kg moving with a velocity of 50m/s collides with another body of mass 5kg moving with a velocity of 10m/s in t
Alekssandra [29.7K]

ΔK = -2334.66J.  The kinetic energy loss is -2334.66J.

This is an example of elastic collision  which means that the two bodies remain united after the collision, as we know the amount of movement is preserved that is called conservation of momentum. So, we can write the equation as follow:

P_{i}=P_{f} Where P_{i} is the initial momentum and P_{f} is the final momentum.

P_{i}=m_{1}.v_{1}+m_{2}.v_{2}

P_{f}=(m_{1}+m_{2}).v_{f}

m_{1}.v_{1}+m_{2}.v_{2}=(m_{1}+m_{2}).v_{f}

v_{f}=\frac{m_{1}.v_{1}+m_{2}.v_{2}}{(m_{1}+m_{2})}

Substituting the values:

v_{f}=\frac{(7kg)(50\frac{m}{s})+(5kg)(10\frac{m}{s})}{(7kg+5kg)}

v_{f}=\frac{350kg\frac{m}{s} +50kg\frac{m}{s} }{12kg}

v_{f}=\frac{400kg\frac{m}{s} }{12kg}=33.33\frac{m}{s}

After the collision the bodies are united and move at the speed of 33.33 m/s.

To calculate the kinetic energy lost in the impact we only have to calculate the energy of each body before the impact and compare it with the energy of the whole after the impact.

ΔK = K_{f}-K_{i}

ΔK = \frac{1}{2}(m_{1}+m_{1})(v_{f})^{2}-[\frac{1}{2}m_{1}(v_{1})^{2}+\frac{1}{2}m_{2}(v_{2})^{2}]

Substituting the values:

ΔK = \frac{1}{2}(7kg+5kg)(33.33\frac{m}{s} )^{2}-[\frac{1}{2}(7kg)(50\frac{m}{s} )^{2}+\frac{1}{2}(5kg)(10\frac{m}{s} )^{2}]

ΔK = \frac{1}{2}(12kg)(1110.89\frac{m^{2}}{s^{2}})-[\frac{1}{2}(7kg)(2500\frac{m^{2}}{s^{2}} )+\frac{1}{2}(5kg)(100\frac{m^{2}}{s^{2}})]

ΔK = \frac{1}{2}(13330.68kg\frac{m^{2}}{s^{2}})-[\frac{1}{2}(17500kg\frac{m^{2}}{s^{2}} )+\frac{1}{2}(500kg\frac{m^{2}}{s^{2}})]

ΔK = 6665.34kg\frac{m^{2}}{s^{2}}-(8750kg\frac{m^{2}}{s^{2}}+250kg\frac{m^{2}}{s^{2}})

ΔK = 6665.34kg\frac{m^{2}}{s^{2}}-9000kg\frac{m^{2}}{s^{2}}

ΔK = -2334.66J

3 0
3 years ago
User Location: Inside ViewportViewport Location: Fresh Viewport in downtown San Fransisco, CaliforniaQuery: [Burger King]Result:
KengaRu [80]

Answer:

All of the above

Explanation:

The steps that should be taken for rating the results is as follows

1. Pin location checking

2. Offical website checking for the address purpose

3. The checking should be done for the closer results in the case of non-returning

Therefore all of the above steps are required and taken for rating the results

Hence, the same is to be considered

8 0
3 years ago
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