Answer:
I am not exactly sure what you are talking about. A dictionary weighs about 1kg. 1kg is equal to 2.2 lbs, or about a quart of milk.
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Answer:
Another metaphor that can help explain energy quantization at the atomic level is the number of teams at different stages in the Football World Cup tournament taking each stage as a given amount of energy gained by the teams at that stage as follows;
Stage 1 Group Stage
The number of teams in the group stage = 32, Energy per team = 1
Knock out stages
Round of 16
The number of teams in the round of 16 stage = 16, Energy per team = 2
Semi final
The number of teams in the semi final stage = 8, Energy per team = 4
Quarter final
The number of teams in the quarter final stage = 4, Energy per team = 8
Final
The number of teams in the semi final stage = 2, Energy per team = 16
The winning team
The number of teams that win the World Cup = 1, Energy of the team = 32
As seen as each team has a specific energy level at each stage of the world cup and there can not any energy value that is an intermediate value of the energy of the teams each at each stage, so also at the atomic level particles within the atom and therefore the atom itself can possess only specific quantum of energy values in a given level or state.
Explanation:
hmax = 5740.48 m. The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.
This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.
V₀ = 420m/s and θ₀ = 53.0°
So, when the cannonball is fired it has horizontal and vertical components:
V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s
V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s
When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:
Vy = V₀y - g tₐ = 0
tₐ = V₀y/g
tₐ = (335.43m/s)/(9.8m/s²) = 34.23s
Then, the maximum height is reached in the instant tₐ = 34.23s:
h = V₀y tₐ - 1/2g tₐ²
hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²
hmax = 11481.77m - 5741.29m
hmax = 5740.48m
when we find the distance we will add all the blocks so
distance = 6+6+4
distance = 14blocks
when we find the displacement we will add and minus too
As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>