Answer:
It allows electrons to flow from one part of the circuit to another
when it is closed.
Explanation:
hope this helps <3 !!
Answer & Explanation:
1 N-m = 1 Joule
So 82 kJ of energy put into the system during (i).
45 kJ of heat leaves the system, so 82 kJ - 45 kJ = 37 kJ is remaining.
(ii) requires 100 kJ of energy but only 37 kJ is available, so 100 kJ - 37 kJ = 63 kJ of heat energy must be added to the system.
Answer:
44.3 m/s
Explanation:
Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.
What is the magnitude of its velocity just before it strikes the ground ?
The parameters given are:
Height H = 100m
Since the ball is thrown from a top of a building, initial velocity U = 0
Let g = 9.8m/s^2
Using third equation of motion
V^2 = U^2 + 2gH
Substitute all the parameters into the formula
V^2 = 2 × 9.8 × 100
V^2 = 200 × 9.8
V^2 = 1960
V = 44.27 m/s
Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately
Answer: E = 39.54 N/C
Explanation: Electric field can be determined using surface charge density:
where:
σ is surface charge density
is permitivitty of free space (
)
Calculating resulting electric field:
![E = \frac{[0.3-(-0.4)].10^{-9}}{2.8.85.10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5B0.3-%28-0.4%29%5D.10%5E%7B-9%7D%7D%7B2.8.85.10%5E%7B-12%7D%7D)
E = 39.54
The resulting Electric Field at any point is 39.54N/C.
