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3 years ago

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What is the definition of a vector?

1 answer:

Zina [86]3 years ago

8 0

A quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another.

for ex: A vector quantity has magnitude and direction.

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What is the Octet rule

egoroff_w [7]

Answer:

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3 years ago

Clutter is _______. annoying frustrating death

Sindrei [870]

Answer: _____= beautiful, yet annoying frustrating death

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2 years ago

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What countries could benefit most from solar energy

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Countries longer day for example in the Middle East could benefit more but Alaska has more night like longer night which is why it would hard to benefit from the solar panels there.

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2 years ago

A 2.74 g coin, which has zero potential energy at the surface, is dropped into a 12.2 m well. After the coin comes to a stop in

nata0808 [166]

Answer:

- 0.328J

Explanation:

POTENTIAL ENERGY = mgh

= 0.00274 × 9.81×12.2 here 2.74g = 0.00274kg

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= 0.328J

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3 years ago

John drives a distance of 90 Km to the right at a steady speed of V1=25.00 m/s. Then he stops at the gas station for 10 minutes.

aleksley [76]

a. Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

b. $t=6000\ s$ is the total time taken in the trip

c. $d=126000\ m$ is the total distance

d. $s=54000\ m$ towards right from the starting point.

e. $v_a=21\ m.s^{-1}$

f. $\vec v_a=9\ m.s^{-1}$ towards right.

Explanation:

a.

Speed is a scalar quantity while velocity is a vector quantity.

Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

Speed is a directionless quantity while velocity constitutes direction.

b.

<em>Total time of round trip when we're given:</em>

distance travelled to the right, $d_r=90000\ m$

speed while travelling to the right, $v_r=25\ m.s^{-1}$

time spent at gas station, $t_g=600\ s$

time spent while travelling back towards the left, $t_l=30\times 60=1800\ s$

speed while travelling to the left, $v_{_l}=20\ m.s^{-1}$

<em>Now time taken for travelling towards right:</em>

$t_r=\frac{d_r}{v_r}$

$t_r=\frac{90000}{25}$

$t_r=3600\ s$

<u>Therefore total time taken in the round trip:</u>

$t=t_r+t_l+t_g$

$t=3600+600+1800$

$t=6000\ s$

c.

<em>Now, distance travelled towards left:</em>

$d_l=v_{_l}\times t_l$

$d_l=20\times1800$

$d_l=36000\ m$

<u>Therefore total distance:</u>

$d=d_l+d_r$

$d=36000+90000$

$d=126000\ m$

d.

Now, total displacement:

$s=d_r-d_l$

$s=90000-36000$

$s=54000\ m$ towards right from the starting point.

e.

<u>Average speed:</u>

$v_a=\frac{d}{t}$

$v_a=\frac{126000}{6000}$

$v_a=21\ m.s^{-1}$

f.

<u>Average velocity:</u>

$\vec v_a=\frac{s}{t}$

$\vec v_a=\frac{54000}{6000}$

$\vec v_a=9\ m.s^{-1}$ towards right.

4 0

2 years ago