The answer to your question is,
4 kilometers north
-Mabel <3
<span>Remember that impulse = change in
momentum
this means we compute the momentum of the ball just before impression and just
after; we know the mass, so we find the speeds
the ball falls for 1.5m and will achieve a speed given by energy
conservation:
1/2 mv^2 = mgh => v=sqrt[2gh]=5.42m/s
since it rises only to 0.85 m, we compute the initial speed after power from
the same equation and get
v(after)=sqrt[2*9.81m/s/s*0.85m] = 4.0837 m...
now, recall that momentum is a vector, so that the momentum down has one sign and
the momentum up has a positive sign, so we have
impulse = delta (mv) = m delta v = 0.014 kx (4.08m/s - (-5.42m/s) = 0.133 kgm/s </span>
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m
Answer:
299792458 metres per second
Explanation:
Answer:
a) solar activity -- sudden eruptions of large bubbles of plasma and magnetic energy
and
d) solar flare -- sudden release of magnetic energy
Explanation:
We can start by eliminating the options that are definitely wrong.
A coronal mass ejection is not a relatively cool spot on surface of the sun, in fact such a spot is a sunspot, while a coronal mass ejection occurs when the magnetic field of the sun emerges as a loop. Thus, both options B and E are incorrect, leaving only A, C, and D. Option C makes no sense, as the sun's gravitational field does not 'churn'. Thus, only options A and D are left. A closer look at A and D reveals they are correct; solar flares are in fact sudden releases of magnetic energy, as seen in this quote from UC Berkeley's website; "Solar flares are caused by sudden changes of strong magnetic fields in the Sun's corona.". And solar activity is a blanket term for the effects of eruptions of plasma and magnetic energy from the sun.
