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1 year ago

Do you know what NBA basketball player is this. And what is he doing to stay healthy.

Physics

1 answer:

Ede4ka [16]1 year ago

4 0

Answer:

That's Chris Paul.

Explanation:

He focuses on his body maintenance, he's vegan. He insures he's getting the right nutritional food in his diet. He stretches a lot and does foam rolls.

HOPE THIS HELPS! GOOD LUCK!

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_________ forces exist between objects that are not in contact with each other.

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2 years ago

Scientists use this part of the electromagnetic spectrum to diagnose broken bones.

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3 years ago

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Facts of heat and transfer

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2 years ago

Which formula can be used to solve problems related to the first law of thermodynamics? q = w u q = u – deltaw q = u w q = u – w

Orlov [11]

"Q = ΔU + W" is the equation is used to solve the questions related to "First law of thermodynamics".

<h3> What is the first law of thermodyanamics?</h3>

"First law of thermodynamics" states that "energy" neither created nor destroyed, but it can transfer from "one form of energy" to "another form of energy".

This "First law of thermodynamics" is also called as "law of conversation of energy". The formula for "First law of thermodynamics" of a system is that "change in internal energy of a system" is same as the difference of "heat energy" flows across the " boundaries of a system" and the "work done" on the system.

ΔU = Q - W

Q = ΔU + W

Where, "ΔU" is "change in internal energy", "Q" is "heat transferred and "W" is "work done.

Hence "Q = ΔU + W" is the equation is used to solve the questions related to "First law of thermodynamics".

To know more about the First law of thermodynamics follow

brainly.com/question/15071682

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1 year ago

What is the maximum wavelength a photon can have if it is to possess sufficient energy to cause this dissociation?

Alona [7]

I attached the full question.
We need to calculate the enthalpy change first:
$\Delta H=$(247kJ)-(142.3kJ)=+105.2kJ$
Keep in mind this is the energy per mole, we need energy per atom:
$E=\frac{105200}{6.02 \cdot 10^{23}}$
We can see that this reaction needs the energy to get started (enthalpy change is positive).
The energy of a photon is given with this formula:
$E=\frac{hc}{\lambda}$
We need this photon to have the same energy (or higher) as our enthalpy change:
$105.2=\frac{6.62\cdot 10^{-34}\cdot 3\cdot 10^ 8}{\lambda}\\ \lambda=\frac{6.62\cdot 10^{-34}\cdot 3\cdot 10^ 8}{105.2/(6.02\cdot 10^{23})} \\\lambda=1.138\mu m$
This wavelenght is clasified as near infrared.

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2 years ago