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dimulka [17.4K]
2 years ago
8

A typical current in a lightning bolt is 103 a. estimate the magnetic field 9 m from the bolt (in t). (enter the magnitude.)

Physics
1 answer:
kifflom [539]2 years ago
4 0

The magnetic field is

2.288 \times 10 {}^{ - 6} T

what is magnetic field?

Magnetic field is defined as the relationship between the permittivity of free space,the magnitude of electric current,and distance.

Here is the formula,

B =  \frac{µ0l }{2π R}

here,

B= magnitude of the magnetic field

l= magnitude of electric current

R=distance

µ0=permittivity of free space

Now,using above formula we can calculate the magnetic field

B =  \frac{µ0l }{2π R}

\frac{4\pi \times 10 {}^{ - 7}. \frac{m}{a}  \times 103 }{2\pi \times (9m)}

= 2.288 \times 10 {}^{ - 6} T

Thus,the magnetic field is

= 2.288 \times 10 {}^{ - 6} T

learn more about magnetic field from here: brainly.com/question/28326849

#SPJ4

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In places such as hospital operating rooms or factories for electronic circuit boards, electric sparks must be avoided. A person
FrozenT [24]

Time taken by the rubber-soled shoes to reduce a person's potential from 3.00×10³ V to 100V is 3.91s

The initial potential difference \Delta V_o is related to the final potential difference \Delta V by

\Delta V=\Delta V_{o} e^{-t / \tau}

Our target is to find t, so we rearrange equation (1) for t to be

\Delta V=\Delta V_{o} e^{-t / RC}\\ \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) = \frac{-t}{RC}\\ t= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \tag{2}

The body has a capacitance 150 pF while the foot has a capacitance 80 pF and both are in parallel connection. So, the equivalent capacitance is

C= 150 \mathrm{~pF} + 80 \mathrm{~pF} = 230 \mathrm{~pF}

The shoes of the rubber-soled has resistance R=5000 \mathrm{~M\Omega}. Plug the values for \Delta V, \Delta V_o and C into equation (2) to get the time t.

t&= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \\ &= -( 5000 \times 10^{6} \mathrm{~\Omega})(230 \times 10^{-12} \mathrm{~F}) \ln \left ( \frac{100\mathrm{~V}}{3000 \mathrm{~V}} \right ) \\ &= {3.91 \mathrm{~s}}

Learn more about capacitance here:

brainly.com/question/12644355

#SPJ4

3 0
2 years ago
How should ready-to-eat food be stored after it has cooled?
snow_lady [41]

Answer:

The answer is most likely C.

Ready-to-eat foods are stored at the top of the fridge, away from raw foods so that harmful bacteria cannot transfer from the raw food to the cooked food. Raw meat, poultry and fish in sealed containers to stop them touching or dripping onto other foods.

5 0
2 years ago
. How much work in joules is done by a person who uses a force of 25 N to move a desk 3.0 m?
sergejj [24]
We Know, W = F * s
here, F = 25 N
s = 3 m

Substitute it into the expression,
W = 25 * 3
W = 75 Joule

So, your final answer is 75 J

Hope this helps!

7 0
3 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
2 years ago
A 100 N force is applied to a box at an angle of 60° to the
Anarel [89]

Answer: lift force = 100sin60 = 86.6 N

             pull force = 100sin60 = 50.0 N

Explanation:

8 0
2 years ago
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