Given :
Object A is 71 degrees and object B is 75 degrees .
To Find :
How will thermal energy flow.
Solution :
We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.
So, in the given question energy will flow from object B from object A.
Hence, this is the required solution.
Answer:
h=2.86m
Explanation:
In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

There is no kinetic energy in the initial state, nor potential energy in the end,

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

The inertia of the bodies is given by the equation,



On the other hand the angular velocity is given by

Replacing these values in the equation,

Solving for h,

It's called the periodic table because it arranges the elements the into repeating sets known as periods. this is defined by the <span>covalence of an element and the number of electrons i has in its outermost shell. I feel the the Best answer would be B. sorry if im wrong but i hope i helped :)</span>
Answer:
the angular velocity of the carousel after the child has started running =

Explanation:
Given that
the mass of the child = m
The radius of the disc = R
moment of inertia I = 
change in time = 
By using the torque around the inertia ; we have:
T = I×∝
where
R×F = I × ∝
R×F =
∝
F =
∝
∝ =
( expression for angular angular acceleration)
The first equation of motion of rotating wheel can be expressed as :

where ;
∝ =
Then;


∴ the angular velocity of the carousel after the child has started running =

Answer:
The second one is correct.
Explanation:
=