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boyakko [2]
3 years ago
13

Enter the expression

Physics
1 answer:
vlabodo [156]3 years ago
6 0
I see the word "when..." kind of fading out at the end of the first line.
Whatever comes after it may be important.

If you're just supposed to copy the expression into the box,
then the problem is that you left the 'e' out of it.

I'm guessing that you're supposed to enter whatever the expression becomes
when either  N₀ or  ' t ' has some special value that's in the first line.

Just taking a wild guess here . . . . .

If it's  "Enter the expression ..... , when t=0 ." ,
then the correct answer in the box is     N₀  .

But that's just a wild guess.  As I pointed out, you cut off
the picture in the middle of the word 'when', and I've got
a hunch that there's something important after it.
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Please need help on this
likoan [24]
The answer to this would be ocean floor
4 0
3 years ago
Francium-223 has a half-life of 22 minutes. A Geiger counter gives a reading of 58 counts per minute (cpm) from a sample of fran
polet [3.4K]

Answer:

29 counts per minute (29 cpm)

Explanation:

The half-life of a radioactive isotope is the time needed for the activity of the sample to halve.The half-life of Francium-223 is exactly 22 minutes: this means that its activity after 22 minutes becomes exactly half of its initial value. Since the initial activity of this sample of francium-223 was 58 cpm, the activity after 22 minutes will be

A=\frac{58 cpm}{2}=29 cpm

8 0
3 years ago
A 3.0 kg object is loaded into a toy spring gun, and the spring has a spring constant 750N/m. The object compresses the spring b
kiruha [24]

Answer:

Explanation:

mass of object, m = 3 kg

spring constant, K = 750 n/m

compression, x = 8 cm = 0.08 m

angle of gun, θ = 30°

(a) As the ball is launched, it has some velocity due to the compression in the spring, so it has some kinetic energy.

(b) Let v be th evelocity of ball at the tim eof launch.

by using the conservation of energy

1/2 Kx² = 1/2 mv²

750 x 0.08 x 0.08 = 3 x v²

v = 1.265 m/s

By use of the formula of maximum height

h = \frac{v^{2}Sin^{2}\theta}{2g}

h = \frac{1.265^{2}Sin^{2}30}{2\times 9.8}

h = 0.02 m

h = 2 cm  

4 0
3 years ago
Porfavor ayuden que es pa mañana :v
Tpy6a [65]

Answer:

what language is

thattranslate i will.answer then

3 0
3 years ago
Please answer offering a lot of points and give brainliest pleaseeeee
asambeis [7]

23 is the right answer.

3 0
3 years ago
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