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3 years ago

Which best describes the relationship between the terms “frequency,” “wavelength,” and “hertz”?

Physics

2 answers:

Natali5045456 [20]3 years ago

5 0

Answer:

Frequency is the number of wavelengths, which is measured in hertz.

Explanation:

I have my ways ;)

AleksAgata [21]3 years ago

3 0

Answer:

Explanation:

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Arocket with an initial velocity of 20 m/s another engine that gives it an acceleration of 4 m/s ^ 2 over 10 secondsHow far did

ExtremeBDS [4]

Answer:

50m

Explanation:

Given parameters:

Initial velocity = 20m/s

Acceleration = 4m/s²

Time = 10s

Unknown:

Distance traveled by the rocket = ?

Solution:

To solve this problem use the expression below;

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

final velocity = 0

Insert the parameters and solve;

0² = 20² + 2 x 4 x s

-400 = 8s

s = 50m

Disregard the negative sign because distance cannot be negative.

3 0

2 years ago

Two coffee cups one at 80 degrees c another at 60 degrees c are put into a large cup what is the final temperature of the coffee

8_murik_8 [283]

If you're trying to sum it up, it would be 140 degrees c*, otherwise it would probably be 80 degrees c since its more hotter than 60 degrees

8 0

3 years ago

ANSWER ASAPPPPPPPP BE 100% CORRECT

AfilCa [17]

Mass of a sample of gas doesn't change, no matter what happens to its pressure, volume, or temperature.

7 0

3 years ago

A deuterium atom is a hydrogen atom with a neutron added to its nucleus. Approximate the binding energy of this nucleus, given t

Mademuasel [1]

Answer:

c. 2 MeV.

Explanation:

The computation of the binding energy is shown below

$= [Zm_p + (A - Z)m_n - N]c^2\\\\=[(1) (1.007825u) + (2 - 1 ) ( 1.008665 u) - 2.014102 u]c^2\\\\= (0.002388u)c^2\\\\= (.002388) (931.5 MeV)\\\\=2.22 MeV$

= 2 MeV

As 1 MeV = (1 u) c^2

hence, the binding energy is 2 MeV

Therefore the correct option is c.

We simply applied the above formula so that the correct binding energy could come

And, the same is to be considered

8 0

2 years ago

A certain heat engine takes in 300 J of energy from a hot source and then transfers 200 J of that energy to a colder object. Wha

Greeley [361]

Answer:

The efficiency is 0.33, or 33%.

Explanation:

From the thermodynamics equations, we know that the formula for the efficiency of a heat engine is:

$\eta=1-\frac{Q_2}{Q_1}$

Where η is the efficiency of the engine, Q_1 is the heat energy taken from the hot source and Q_2 is the heat energy given to the cold object. So, plugging the given values in the formula, we obtain:

$\eta=1-\frac{200J}{300J}=0.33$

This means that the efficiency of the heat engine is 0.33, or 33% (The efficiency of an engine is dimensionless).

5 0

3 years ago