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Amanda [17]
2 years ago
10

Which best describes the relationship between the terms “frequency,” “wavelength,” and “hertz”?

Physics
2 answers:
Natali5045456 [20]2 years ago
5 0

Answer:

Frequency is the number of wavelengths, which is measured in hertz.

Explanation:

I have my ways ;)

AleksAgata [21]2 years ago
3 0

Answer:

B

Explanation:

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Suppose that an object is moving along a vertical line. Its vertical position is given by the equation L(t) = 2t3 + t2-5t + 1, w
Tatiana [17]

Answer:

The average velocity is

266\frac{m}{s},274\frac{m}{s} and 117\frac{m}{s} respectively.

Explanation:

Let's start writing the vertical position equation :

L(t)=2t^{3}+t^{2}-5t+1

Where distance is measured in meters and time in seconds.

The average velocity is equal to the position variation divided by the time variation.

V_{avg}=\frac{Displacement}{Time} = Δx / Δt = \frac{x2-x1}{t2-t1}

For the first time interval :

t1 = 5 s → t2 = 8 s

The time variation is :

t2-t1=8s-5s=3s

For the position variation we use the vertical position equation :

x2=L(8s)=2.(8)^{3}+8^{2}-5.8+1=1049m

x1=L(5s)=2.(5)^{3}+5^{2}-5.5+1=251m

Δx = x2 - x1 = 1049 m - 251 m = 798 m

The average velocity for this interval is

\frac{798m}{3s}=266\frac{m}{s}

For the second time interval :

t1 = 4 s → t2 = 9 s

x2=L(9s)=2.(9)^{3}+9^{2}-5.9+1=1495m

x1=L(4s)=2.(4)^{3}+4^{2}-5.4+1=125m

Δx = x2 - x1 = 1495 m - 125 m = 1370 m

And the time variation is t2 - t1 = 9 s - 4 s = 5 s

The average velocity for this interval is :

\frac{1370m}{5s}=274\frac{m}{s}

Finally for the third time interval :

t1 = 1 s → t2 = 7 s

The time variation is t2 - t1 = 7 s - 1 s = 6 s

Then

x2=L(7s)=2.(7)^{3}+7^{2}-5.7+1=701m

x1=L(1s)=2.(1)^{3}+1^{2}-5.1+1=-1m

The position variation is x2 - x1 = 701 m - (-1 m) = 702 m

The average velocity is

\frac{702m}{6s}=117\frac{m}{s}

5 0
3 years ago
Consider a concave spherical mirr or that has focal length f = +19.5 cm.
lidiya [134]

The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

<h3>What is concave mirror?</h3>

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

<h3>Object distance of the concave mirror</h3>

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

  • f is the focal length of the mirror
  • v is the object distance
  • u is the image distance

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

Learn more about concave mirror here: brainly.com/question/27841226

#SPJ1

7 0
1 year ago
An object is 2.0 m in front of a plane mirror. Its image is:?
maria [59]
Planes don’t have mirrors
6 0
3 years ago
The sum of all the forces acting on an <br> object is zero.
marysya [2.9K]

Answer:

Newton's first law states that when the vector sum of all forces acting on an object (the net force) is zero, the object is in equilibrium. If the object is initially at rest, it remains at rest. If it is initially in motion, it continues to move with constant velocity.

Explanation:

3 0
1 year ago
Read 2 more answers
A light bulb is rated at 25 w when operated at 110 v. how much charge enters (and leaves) the light bulb in 1.0 hour?
DedPeter [7]

According to the current, the charge is 818.18 coulombs.

We need to know about current to solve this problem. Current can be defined as the flow rate of charge through the medium. It can be determined as

I = Q / t

where I is current, Q is charge and t is time.

From the question above, we know that

P = 25 W

V = 110 V

h = 1 hour = 3600 second

Calculate the current

P = V . I

25 = 110 . I

I = 0.23 A

By substituting the given parameters, we can calculate the charge

I = Q / t

0.23 = Q / 3600

Q = 818.18 coulombs

Hence, the charge is 818.18 coulombs.

Find more on current at: brainly.com/question/24858512

#SPJ4

4 0
1 year ago
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