Answer:
Well the definition of an application is the act of putting to a special use or purpose so lam assuming that you want specific uses that scientists make of gravity in their work.
Well our first application has helped us to send satellites around the solar system with what Nasa calls gravity assist. Using a particular planets gravity to slingshot a satellite to another destination. Look it up.
The next application much simpler but here on Earth. There are many hydro-electric power stations in use all over the world. Water is stored at a high level and released falling 100s of metres to a turbine where it generates electricity.
Hope that helps.
Explanation:
Answer:
option C
Explanation:
given,
Force on the object = 10 N
distance of push = 5 m
Work done = ?
we know,
work done is equal to Force into displacement.
W = F . s
W = 10 x 5
W = 50 J
Work done by the object when 10 N force is applied is equal to 50 J
Hence, the correct answer is option C
a = 7.8 m/s^2
Explanation:
Let Fnet = net force = ma
m = mass of the skydiver
a = acceleration caused by Fnet
W = weight = mg
f(air) = frictional force due to air resistance
Fnet = W - f(air)
= (100 kg)(9.8 m/s^2) - (200 N)
= 780 N
Therefore, the acceleration of the skydiver due to Fnet is
a = Fnet/m
= (780 N)/(100 kg)
= 7.8 m/s^2
Answer:
t= 137.5 s
Explanation:
So if we are wanting to figure out how long it takes runner B to catch runner A. we must first set the slope of each runner equal to one another
<u>Slopes:</u>
Runner A: y = 7.50x + 55
Runner B: y = 7.90 x
sooooo
7.50 x + 55 = 7.90 x
- 7.50 x - 7.50 x
55 = .40 x
55/.40 = .40 x / .40
x = 137.5 s
t= 137.5 s
7.50 * 137.5 + 55 =1086.25 m
7.90 * 137.5 = 1086.25 m