A Yugo can accelerate from rest to a speed of 28 m/s in 20 s. What is the average acceleration of the car? What distance does it
1 answer:
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Answer:
a) Y component of the vector =15.54 m
b) Vector magnitude = 21.6 m
Explanation:
The given vector makes 44 degree angle with Y axis, as given. This is same as 90 -44 = 46 degrees with the horizontal or X axis.
b) X component of the given vector = = A cos 46 =15
⇒ A = 15/cos 16 = 21.6 m = Total vector magnitude.
a) Y component of the vector = 21.6 sin 46 = 15.54 m
b) A = 21.6 m