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Len [333]
2 years ago
5

A Yugo can accelerate from rest to a speed of 28 m/s in 20 s. What is the average acceleration of the car? What distance does it

travel in this time
Physics
1 answer:
harina [27]2 years ago
6 0

Answer:

Explanation:

a=28/20

a=1.4 m/s²

V²=v0²+2a.D

28²=0+2x1.4D

784 = 2.8D

D = 280 m

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3 years ago
What is the difference between each distance traveled and displacement travled
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8 0
3 years ago
Remember to include your data, equation, and work when solving this problem.
andrezito [222]

Answer:

F = 0.00156[N]

Explanation:

We can solve this problem by using Newton's proposed universal gravitation law.

F=G*\frac{m_{1} *m_{2} }{r^{2} } \\

Where:

F = gravitational force between the moon and Ellen; units [Newtos] or [N]

G = universal gravitational constant = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1= Ellen's mass [kg]

m2= Moon's mass [kg]

r = distance from the moon to the earth [meters] or [m].

Data:

G = 6.67 * 10^-11 [N^2*m^2/(kg^2)]

m1 = 47 [kg]

m2 = 7.35 * 10^22 [kg]

r = 3.84 * 10^8 [m]

F=6.67*10^{-11} * \frac{47*7.35*10^{22} }{(3.84*10^8)^{2} }\\ F= 0.00156 [N]

This force is very small compare with the force exerted by the earth to Ellen's body. That is the reason that her body does not float away.

6 0
2 years ago
For numbers 2 and 3, which one is compression and which one is rarefaction?
DENIUS [597]
Compression is above the equilibrium and rarefaction is below
5 0
3 years ago
Help please!!!
exis [7]

Answer:

5 years worth of work (aka all of the homework i currently have)

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