The speed of the large fish after eating the small fish is 4.76 m/s.
We can apply the law of momentum conservation to calculate the speed of the large fish.
Let the velocity of the large fish after eating small fish is v.
According to law of momentum conservation
m1u1+m2u2=(m1+m2)v
here, m1 is the mass of the large fish, u1 is the initial speed of larger fish, ml is the mass of the small fish, u2 is the initial speed of small fish
10*5+0.5*0=(10+0.5)v
v=4.76 m/s
Answer:
330Ns
Explanation:
Given parameters:
Mass of the box = 5kg
Initial velocity = 0m/s
Force applied = 15N
Time = 22s
Unknown:
Impulse = ?
Final momentum = ?
Solution:
The impulse of the box can be determined using the expression below:
Impulse = Force x time
Impulse = 15 x 22 = 330Ns
The final momentum is the same as this impulse
The impulse and the final momentum is 330Ns
GiveN:
- Initial velocity = 9.8 m/s²
- Accleration due to gravity = -9.8 m/s²
- Time taken = 1 s
To FinD:
- Final velocity of the ball?
Step-by-step Explanation:
Using the first Equation of motion,
⇒ v = u + gt
⇒ v = 9.8 + -9.8(1)
⇒ v = 0 m/s
The final velocity is hence <u>0</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>
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Note:</h3>
- While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.
- You can consider positive above the ground and negative for towards it.