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3 years ago

Which of these statements best describes an effect of changes in Earth's magnetic field?

Physics

2 answers:

Alona [7]3 years ago

8 0

Answer:

The magnetic north and south poles of Earth are interchanged.

Explanation:

Earth acts as a huge bar magnet due to the presence of iron and nickel in its core. The magnetic field surrounding Earth is known as magnetosphere which constantly protects from solar wind. Auroras are visible in the sky when charged particles from the sun interact with the magnetic field of the earth especially near the poles where strength of the magnetic field is maximum.

Over the years, the magnetic field might weaken as it is continuously repelling the charged particles from the Sun. As a consequence, the poles of this magnetic field might reverse.

Thus, changes in Earth's magnetic field can reverse the poles.

Sveta_85 [38]3 years ago

6 0

The only statement that makes sense as to which one describes an effect of changes in Earth's magnetic field is the first one - <span>Southern lights are seen at high altitude places like Alaska.
Normally, Southern lights are seen around the South Pole, which means that it is quite odd for them to be seen in Alaska, which is near the North Pole.</span>

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An automobile tire having a temperature of −1.6 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 22 lb/in2 . What

r-ruslan [8.4K]

Answer:

25.8 lb/in²

Explanation:

Gay-Lussac's law tells us that given an ideal gas of a certain mass has a constant volume, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

$\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} } \\\\\frac{22}{-1.6+273.15} =\frac{P_{2} }{45+273.15} \\\\P_{2} = \frac{22*318.15}{271.55} = 25.8lb/in^{2}$

4 0

3 years ago

An object experiences an acceleration of -6.8 m/s2. As a result, it accelerates from 54 m/s to a complete stop. How much dista

inessss [21]

Answer:

The distance traveled during its acceleration, d = 214.38 m

Explanation:

Given,

The object's acceleration, a = -6.8 m/s²

The initial speed of the object, u = 54 m/s

The final speed of the object, v = 0

The acceleration of the object is given by the formula,

a = (v - u) / t m/s²

∴ t = (v - u) / a

= (0 - 54) / (-6.8)

= 7.94 s

The average velocity of the object,

V = (54 + 0)/2

= 27 m/s

The displacement of the object,

d = V x t meter

= 27 x 7.94

= 214.38 m

Hence, the distance the object traveled during that acceleration is, a = 214.38 m

3 0

3 years ago

Which is a chemical property that can be used to identify calcium carbonate?

Zina [86]

I think the answer is d i think

5 0

3 years ago

Suppose you find yourself in your friend's third floor apartment building when you smell smoke coming from outside the door. you

Alborosie

(a) Because the tension in the rope would be larger than the maximum value allowed

When you are sliding down the slope, there are two forces acting on you:

- Your weight, $W=mg$ , acting downward, where

m = 70 kg is your mass

g = 9.8 m/s^2 is the acceleration of gravity

- The tension in the rope, T, acting upward

Therefore, the equation of motion is

$T-mg=ma$

where a is the acceleration.

If you want to slide at constant speed, then the acceleration must be zero:

$a = 0$

And so the equation becomes

$T-mg=0$

This means that the tension in the rope must be:

$T=mg=(70 kg)(9.8 m/s^2)=686 N$

Which is larger than the maximum tension allowed in the rope (500 N), so the rope will break.

(b) $2.66 m/s^2$ downward

Again, we must refer to the equation of the forces:

$T-mg=ma$

In this case, we want the tension in the rope to be the maximum allowed value,

T = 500 N

the other data are

m = 70 kg is your mass

g = 9.8 m/s^2 is the acceleration of gravity

Substituting into the equation, we can find the corresponding value of acceleration:

$a=\frac{T-mg}{m}=\frac{500-(70)(9.8)}{70}=-2.66 m/s^2$

where the negative sign means the acceleration is downward.

8 0

4 years ago

A locomotive is pulling 8 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (wi

nikitadnepr [17]

Answer:106560 N

Explanation:

Given

Let Tension between 2 and 3 car be $T_{23}$ and between 3 &4 is $T_{34}$

$T_{23}-T_{34}=ma$

mass of freight car =37,000 kg

acceleration of car $=0.48 m/s^2$

$T_{34}$ is accelerating all freights behind 3

therefore

$T_{34}=5\times ma$

$T_{34}=5\times 37000\times 0.48=88,800 N$

Thus

$T_{23}=T_{34}+ma$

$T_{23}=88,800+37000\times 0.48=88,800+17,760=106560 N$

4 0

4 years ago