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Doss [256]
3 years ago
9

An astronaut 100m from the spaceship observes a 200kg meteoroid that drifts toward the shop at 10m/sec. If the astronaut can gai

n a hold on the meteoroid and the astronaut’s rocket gun is capable of delivering a force of 100N, can the meteoroid be stopped before it hits the spaceships?
Physics
1 answer:
Fynjy0 [20]3 years ago
8 0

No

Refer to the attachment for calculations

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If a 4 engine jet accelerates down a runway at 8.7 m/s^2, Suppose now that all 4 engins are operational on the jet from the prev
soldi70 [24.7K]

Answer:

5.22m/s^2

Explanation:

One of the first propulsion characteristics given in the example is that all engines are equal.

In this way if we have 4 engines running at the same time, it means that its capacity is 100%.

Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.

However, the question is, what would happen if 2.4 "Engines" now work.

To do this then we make a simple equivalence,

If 4 engines is the equivalent of 100%, when would it be 2.4 engines?

X = \frac{2.4 * 100\%} { 4 }= 60\%

In this way it would mean that the body could be driven to 60% of its total.

So

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3 0
3 years ago
If you have lifted 10 pounds 2 feet, you have done ___ foot-pounds of work.
nasty-shy [4]
Work = Force x distance
          (10 pounds)(2 feet)
Work = 20 foot-pounds of work

hope this helps :)


8 0
3 years ago
Who invented the telephone?
krok68 [10]
<h2>Answer:</h2><h3><em><u>Alexander Graham Bell</u></em></h3><h2>Explanation:</h2>

Alexander Graham Bell is often credited as the inventor of the telephone since he was awarded the first successful patent.

5 0
2 years ago
Read 2 more answers
A loader sack of total mass
vampirchik [111]

Question: A loader sack of total mass

is l000 grams falls down from

the floor of a lorry 200 cm high

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gravity of the load.​

Answer:

19.6 Joules

Explanation:

Applying

W = mgh........................ Equation 1

Where W = Workdone by gravity on the load, m = mass of the loader sack, h = height, g = acceleration due to gravity

From the question,

Given: m = 1000 grams = (1000/1000) kilogram = 1 kg, h = 200 cm = 2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

W = (1×2×9.8)

W = 19.6 Joules

Hence the work done by gravity on the load is 19.6 Joules

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3 years ago
Why is it good practice for scientists to repeat trails
tensa zangetsu [6.8K]
It makes the data thet they collect more reliable so if they need the data again, they have already tested it a few times so therefor they know that it is right.
8 0
3 years ago
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