Answer:
Angular velocity is same as frequency of oscillation in this case.
ω = 
x ![[\frac{L^{2}}{mK}]^{3/14}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BL%5E%7B2%7D%7D%7BmK%7D%5D%5E%7B3%2F14%7D)
Explanation:
- write the equation F(r) = -K
with angular momentum <em>L</em>
- Get the necessary centripetal acceleration with radius r₀ and make r₀ the subject.
- Write the energy of the orbit in relative to r = 0, and solve for "E".
- Find the second derivative of effective potential to calculate the frequency of small radial oscillations. This is the effective spring constant.
- Solve for effective potential
- ω = x
This correct answer would be C
Answer:
Technique to reduce Noise, magnetic attraction and Twitching sensation
Explanation:
Changing magnetic fields cause loud knocking noise this can be overcome by ear protection.
Strong and Static magnetic fields attract magnetic objects that can be avoided by screening of people and objects before entering in that area.
Twitching Sensation due to nerve stimulation can be avoided by reducing the exposure to magnetic field.
Please mark branliest if you are satisfied with the answer. Thanking you in anticipation.
1. The mass number is protons + neutrons = mass number. In this case, we have protons + neutron = 164.The atomic number is simply the number of protons so we have 43 + neutrons = 164. Subtracting 43 from both sides we get neutrons = 121.
2. = 4
3. The number of protons in the nucleus does not equal the number of neutrons.
A=mass number:
Z=atomic number (= number of protons)
N=number of neutrons:
A=Z+N
If the number of protons in the nucleus is equal the number of neutrons , we would have an even mass number; because Z=N=x; then A=x+x=2x (this is always an even number) but 23 is an odd number, therefore the number of protons in the nucleus does not equal the number of neutrons.
Answer:
After finding the electric potential VP at point P = Q/Чπϵ₀L ㏑(1+
)
Explanation:
I believe it is a part C question.
The derivative of V and P will be directly proportional to the differential dq and the inverse of Чπϵ₀δ........
Please find detailed solution in the attached picture as i believe that is the answer to the part C question you are seeking for.
