In spring mass system we know that angular frequency is given as
f = 8.38 Hz
now we know that speed of SHM at its extreme position is given by
here we know that
A = 17.5 cm
so maximum speed is 9.21 m/s
As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o
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According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>
In other words, this law states a relation between the orbital period of a body (moon, planet, satellite) orbiting a greater body in space with the size
of its orbit.
This Law is originally expressed as follows:
<h2>
Where;
is the Gravitational Constant and its value is
is the mass of Jupiter
is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
<h2>
Then:
<h2>
Which is the same as:
<h2>
Therefore, the answer is:
The orbital period of Io is 42.482 h
The object’s resultant angle of motion with the +x-axis after the collision is 47°
<span>From object A:
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
Now, we know, tan</span>Ф =
⇒tanФ =
⇒tanФ = 1.088
⇒ Ф =
1.088
= 47.4 ≈ 47
<span>From object A:
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
Now, we know, tan</span>Ф =
⇒tanФ =
⇒tanФ = 1.088
⇒ Ф =
= 47.4 ≈ 47