Answer:
A lone neutron spontaneously decays into a proton plus an electron.
Explanation:
In an atom, nuclei contain protons and neutrons, which are the fundamental particles of an atom. Neutrons are stable and uncharged particles inside a nucleus.
For 15 times during its lifetime, a free neutron decays and breaks down into more smaller particles.This breakdown causes problems in nuclear reactors, as they start decaying and emit radiations of different wavelengths.
A neutron undergoes the decaying process to produce an electron, a proton, and energy.
The reaction of neutron decay:
n0 → p+ + e− + νe
Answer:
1375J
Explanation:
The gravitational potential/potential energy of the at the top of the tree which is the energy by virtue of its position.
P.E = mgh
mass = m
Acceleration due to gravity = g
height = h
At the top of the tree, the value of h (height) is high resulting in the gravitational potential. When the cat lands on the ground, the value of h is zero, the the gravitational potential would be zero and all the potential energy have been converted to other forms of energy.
Therefore, the total gravitational potential store is equal to the maximum amount of energy that can be transferred which is equal to 1375J.
No it all takes 9 or 10 months
Answer:
(a) The constants required describing the rod's density are B=2.6 and C=1.325.
(b) The mass of the road can be found using 
Explanation:
(a) Since the density variation is linear and the coordinate x begins at the low-density end of the rod, we have a density given by

recalling that the coordinate x is measured in centimeters.
(b) The mass of the rod can be found by having into account the density, which is x-dependent, and the volume differential for the rod:
,
hence, the mass of the rod is 126.6 g.
Answer:
The orbital period of the planet is 387.62 days.
Explanation:
Given that,
Mass of planet
Mass of star 
Radius of the orbit
Using centripetal and gravitational force
The centripetal force is given by


We know that,

....(I)
The gravitational force is given by
....(II)
From equation (I) and (II)

Where, m = mass of planet
m' = mass of star
G = gravitational constant
r = radius of the orbit
T = time period
Put the value into the formula





Hence, The orbital period of the planet is 387.62 days.