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VikaD [51]
3 years ago
13

Maximum power transfer theorem iz related to which chapter of physics Class 12

Physics
1 answer:
Tpy6a [65]3 years ago
8 0
DaddyFed is right, it would be all of them.
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Which way will the people on the right move? Why? Plz answer
Scrat [10]
Probably to the right because the force on the left is greater and will therefore overpower the 2N force and push to the right
3 0
3 years ago
During spring tide, the sun and moon are aligned. Which statement below best describes the tidal range during a spring tide?
e-lub [12.9K]

Answer:

Explanation:

A ) The smallest tidal ranges are less than 1 m (3 feet). The highest tides, called spring tides, are formed when the earth, sun and moon are lined up in a row. This happens every two weeks during a new moon or full moon. Smaller tides, called neap tides, are formed when the earth, sun and moon form a right angle.

C ) The most extreme tidal range occurs during spring tides, when the gravitational forces of both the Moon and Sun are aligned (syzygy), reinforcing each other in the same direction (new moon) or in opposite directions (full moon).

4 0
2 years ago
Read 2 more answers
The variable ______________ describes how quickly something moves.
IrinaK [193]

it's up in Gogle trust me

8 0
3 years ago
A person is standing on an elevator initially at rest at the first floor of a high building. The elevator then begins to ascend
GREYUIT [131]

Answer:

The found acceleration in terms of h and t is:

a=\frac{h}{5(t_1)^2}

Explanation:

(The complete question is given in the attached picture. We need to find the acceleration in terms of h and t in this question)

We are given 3 stages of movement of elevator. We'll first model them each of the stage one by one to find the height covered in each stage. After that we'll find the total height covered by adding heights covered in each stage, and equate it to Total height h. From that we can find the formula for acceleration.

<h3></h3><h3>Stage 1</h3>

Constant acceleration, starts from rest.

Distance = y = \frac{1}{2}a(t_1)^2

Velocity = v_1=at_1

<h3>Stage 2</h3>

Constant velocity where

Velocity = v_o=v_1=at_1

Distance =

<h3>y_2=v_2(t_2)\\\text{Where~}t_2=4t_1 ~\text{and}~ v_2=v_1=at_1\\y_2=(at_1)(4t_1)\\y_2=4a(t_1)^2\\</h3><h3 /><h3>Stage 3</h3>

Constant deceleration where

Velocity = v_0=v_1=at_1

Distance =

y_3=v_1t_3-\frac{1}{2}a(t_3)^2\\\text{Where}~t_3=t_1\\y_3=v_1t_1-\frac{1}{2}a(t_1)^2\\\text{Where}~ v_1t_1=a(t_1)^2\\y_3=a(t_1)^2-\frac{1}{2}a(t_1)^2\\\text{Subtracting both terms:}\\y_3=\frac{1}{2}a(t_1)^2

<h3>Total Height</h3>

Total height = y₁ + y₂ + y₃

Total height = \frac{1}{2}a(t_1)^2+4a(t_1)^2+\frac{1}{2}a(t_1)^2 = 5a(t_1)^2

<h3 /><h3>Acceleration</h3>

Find acceleration by rearranging the found equation of total height.

Total Height = h

h = 5a(t₁)²

a=\frac{h}{5(t_1)^2}

6 0
3 years ago
A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air
ValentinkaMS [17]

Answer:

the value of the final pressure is 0.168 atm

Explanation:

Given the data in the question;

Let p₁ be initial pressure, v₁ be initial volume.

After expansion, p₂ is final pressure and v₂ is final volume.

So using the following equations;

p₁v₁ = nRT

p₂v₂ = nRT

hence, p₁v₁ = p₂v₂

we find p₂

p₂ = p₁v₁ / v₂

given that; initial volume v₁ = 0.175 m³, Initial pressure p₁ = 0.350 atm,

final volume v₂ = 0.365 m³

we substitute

p₂ = ( 0.350 atm × 0.175 m³ ) / 0.365 m³

p₂ = 0.06125 atm-m³ / 0.365 m³

p₂ = 0.168 atm

Therefore, the value of the final pressure is 0.168 atm

7 0
2 years ago
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