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arsen [322]
3 years ago
11

Which of these solution is most basic

Chemistry
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

There is nothing to answer lol

Katarina [22]3 years ago
8 0
Where’s the solutions??
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Describe the process of convection and how it contributes to seafloor spreading
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Seafloor spreading and other tectonic activity processes are the result of mantle convection. ... Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense.

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How are amplitude modulation and frequency modulation techniques similar?
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Calculate the molar mass of the following compound: Ca3P2
julia-pushkina [17]

Answer:

The molar mass of the compound given is 182.182 g/mol.

Explanation:

To calculate the molar mass of the compound, we must multiply the number of moles of each element by the the individual molar mass of each element and add them together.

Let's start with Calcium.  The molar mass of Calcium is 40.078.  In this compound, we have three moles of Calcium, so we should multiply this number by 3.

40.078 g/mol * 3 mol = 120.234 g

Now, let's do the same for Phosphorus.

30.974 g/mol * 2 g/mol = 61.948 g

To find the molar mass of the entire compound, we should add these two values together.

120.234 g + 61.948 g = 182.182 g

Therefore, the correct answer is 182.182 g/mol.

Hope this helps!

6 0
3 years ago
A buffer solution contains 0.496 M KHCO3 and 0.340 M K2CO3. If 0.0585 moles of potassium hydroxide are added to 250. mL of this
aev [14]

Answer:

pH = 10.9

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:

n_{CO_3^{2-}}=0.34mol/L*0.250L+0.0585mol=0.1435mol\\\\n_{HCO_3^{-}}=0.34mol/L*0.250L-0.0585mol=0.0265mol

The resulting concentrations are:

[CO_3^{2-}]=\frac{0.1435mol}{0.25L}=0.574M \\

[HCO_3^{-}]=\frac{0.0265mol}{0.25L}=0.106M

Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:

pH=10.2+log(\frac{0.574M}{0.106M} )\\\\pH=10.9

Which makes sense since basic OH⁻ ions were added.

Regards!

6 0
3 years ago
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