Answer:
you gotta call her manager dead or alive
Answer:
237.9 amu
Explanation:
Given data:
Abundance of U-234 = 0.0054 %
Abundance of U-235 = 0.7204%
Abundance of U-238 = 99.2742%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass / 100
Average atomic mass = (0.0054×234)+(0.7204×235) +(99.2742×238) /100
Average atomic mass = 1.2636+ 169.294+ 23627.2596 / 100
Average atomic mass = 23797.8172/ 100
Average atomic mass = 237.9 amu.
Answer:
the oldest rocks are in the center of the dome structure.
Explanation:
To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration of the stock
solution, V1 is the volume of the stock solution, M2 is the concentration of
the new solution and V2 is its volume.
1.75 M x V1 = 0.100 M x 2.0 L
V1 = -.11 L
