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pav-90 [236]
2 years ago
12

Macoy Inda

Chemistry
1 answer:
Andreyy892 years ago
3 0

Answer:

? the question isn't clear

Explanation:

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One mole of which of these compounds contains two moles of hydrogen atoms? f NaOH g H2S h CH4 j NH3
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Indicate whether each of the following statements is correct or incorrect.1)Every Bronsted-Lowry acid is also a Lewis acid2)Ever
Hunter-Best [27]

Answer:

1) correct

2) incorrect

3) correct

4)incorrect

Explanation:

1) A Lewis acid is a substance that accepts a nonbonding pair of electrons.

A Bronsted-Lowry acid is a substance that donates a proton H⁺

Since the donation of a proton involves the acceptance of a pair of electrons, every Bronsted-Lowry acid is also a Lewis acid.

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4 0
3 years ago
Enthalpy of <br><br> CH4(g) + 2NO2(g) -&gt; N2(g) + CO2(g) + 2H2O(l)
stira [4]

Answer:

-177.9 kJ.

Explanation:

Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.

5 0
2 years ago
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